0
Want this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
Determine the number of formula units that are in 0.688 moles of AgNO3?
0.688 moles*6.02x1023=4.14x1023 Formula units
How many formula units of salt make up 10 moles?
10 formula units
How many moles are equivalent to 3.6x1024 formula units of MgBr2?
The answer is 5,978 moles.
How much magnesium sulphide can be made from 1.0gram of magnesium and 1.0gram of sulphur?
The formula of magnesium sulphide is MgS, showing that a formula unit has one atom of each element. The gram atomic mass of magnesium is 24.305 and that of sulphur is 32.06. Therefore, when magnesium and sulphur are present in equal amounts by mass, sulphur is the limiting reactant. 1.0/32.06 or 0.031 moles of sulphur atoms are present. Therefore, the maximum amount of MgS that can result from reaction is 0.031 formula units of MgS. The gram formula mass of MgS is 56.365, so that 0.031 formula units of MgS will have a mass of 1.7 grams, to the justified number of significant digits.
How many formula units are in 5.38 moles of potassium sulfate?
The answer is 32,4.10e23.
What is the number of formula units that are in 5.68 moles of magnesium oxide?
5.68 mol MgO x 6.02E23 formula units / 1 mol = 3.42E24 Formula Units
How many formula units are there in 2.5 grams of Magnesium Chloride?
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
Determine the number of formula units that are in 0.688 moles of AgNO3?
0.688 moles*6.02x1023=4.14x1023 Formula units
How many moles of ammonium ions are in 8.903 g of ammonium carbonate?
The most common form of solid ammonium carbonate is a hydrate with formula (NH4)2CO3.H2O and a gram formula unit mass of 114.10. The formula shows that each formula unit contains 2 ammonium ions. The number of formula units of ammonium carbonate is 8.903/114.10 or 0.078028. The number of formula units of ammonium ions is twice this, or 0.1561, to the justified number of significant digits.
How many formula units make up 12.2g of magnesium chloride?
12.2/95.211 = .1281 moles MgCl2. .1281 x 6.022x1023 = 7.7177x1022 molecules
How many formula units of salt make up 10 moles?
10 formula units
How many moles of CaCl2 are in 2.00 1024 formula units?
The answer is 3,33 moles.
How many moles are equivalent to 3.6x1024 formula units of MgBr2?
The answer is 5,978 moles.
How many formula units of sodium acetate are in 0.87 moles of sodium acetate?
How many formula units of sodium acetate are in 0.87 moles of sodium acetat
How many moles of nitrogen are in 650 moles of ammonium carbonate How many grams of this compound supply this much nitrogen?
The formula unit for the usual form of solid ammonium carbonate is (NH4)2CO3.H2O. This formula shows that each formula unit contains two atoms of nitrogen. Because nitrogen forms diatomic molecules at standard temperature and pressure, the number of moles of nitrogen is therefore the same as the number of formula units of ammonium carbonate, stated to be 650. The gram formula unit mass of this solid ammonium carbonate is 114.10. Therefore, 114.10(650) or 7.42 X 103 grams of the solid, to the justified number of significant digits, will be required.
The formula for an ionic compound such as magnesium chloride is expressed in terms of?
formula units
How many formula units make up 33.8 g of magnesium chloride (MgCl2)?
0,355 formula units make up 33,8 g of magnesium chloride (MgCl2).
