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The answer is 5,978 moles.

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Q: How many moles are equivalent to 3.6x1024 formula units of MgBr2?
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How many ions does MgBr2 have?

One formula unit of MgBr2 has three ions; one Mg2+ ion and two Br- ions. One mole of MgBr2 formula units has one mole of Mg2+ ions and two moles of Br- ions, for a total of three moles of ions.


How many anions are there in 2.50 g of MgBr2?

2.50 g MgBr2 x 1 mole MgBr2/184 g x 2 mole Br/mole MgBr2 = 0.0272 moles Br^-0.0272 moles Br^- x 6.02x10^23 anions/mole = 1.6x10^22 anions


If you have g of beryllium how many moles is this equivalent to?

The formula is: number of moles = g Be/9,012.


What is the mass of 7 moles of MgBr2?

The molar mass of MgCl2 = 95.211 g/mol


How many moles of bromide ions are present in 750.0 mL of 1.35 M MgBr2?

2.03mol


How many formula units are in 0.75 moles of AlCl3?

0,75 moles of AlCl3 (anhydrous) is equivalent to 100,005 g.


In the formula for sodium phosphate Na3PO4 how many moles of sodium are represented?

the formula does not show how many moles are in a compound, but it tells how many atoms of an element that are in the compound...


How many moles are in 60g of NaCl?

The term molecule is not adequate for an ionic compound; correct is formula unit.60 g NaCl contain the equivalent of 1,026 formula units.


How many formula units are in this same 0.665mol NaCl?

0,665 moles NaCl is equivalent to 38,86 g.


What is the Molarity of a substance that contains 4.13 grams of magnesium bromide in 845 liters of a solution?

To find the molarity of the substance, divide the moles of the substance by the volume of the solution in liters. First, calculate the moles of magnesium bromide: Convert grams to moles by dividing the given mass by the molar mass of magnesium bromide (184.1 g/mol). Moles of magnesium bromide = 4.13 g / 184.1 g/mol = 0.0224 mol. Next, divide the moles by the volume of the solution in liters: Molarity = 0.0224 mol / 845 L ≈ 0.00003 M (rounded to 3 significant figures).


Determine the number of formula units that are in 0.688 moles of AgNO3?

0.688 moles*6.02x1023=4.14x1023 Formula units


How many moles of base are needed to neutralize 2 mol of acid for HNO3 plus KOH?

Since both the acid and the base have equivalent weights equal to their formula weights, 2 moles of KOH are needed to neutralize 2 moles of nitric acid.