I would tell, no reaction will occur the way the question has been asked.
The positive species which may attack on carbon or a pi bonds are electrophile as Cl+, NO2+ etc. but H+ and Positive metallic ions are not electrophile .
The H-C bond and each C-Cl bond are covalent bonds.
Butane itself is C4H10, however when a bromine atom is attached to the second carbon, it becomes C4H9Br as one hydrogen is replaced by the bromine.
The S-Cl bond is polar. The electronegativity difference between S and Cl is 0.58, which means it is polar.
Three - C = carbon H = hydrogen Cl = chlorine
It contains Cl,C,H atoms. C,Cl2,H2 are the sources.
Place C in the center and attach 2 Cl atoms to it, and attach 2 H atoms to it. Then place 3 lone pairs of electrons around each Cl atom. That is the Lewis structure.
. . . . :Cl: :Cl: l l C = C l l :Cl: :Cl: ' ' ' ' Hope it helps!
cl / H - C - cl / cl
the difference is that in pvc h-c is replaced with c-cl. c-cl is less oxidisible by air while h-cl is oxidisable hence flamable while cl-c doesn't
H2 + Cl2 --> 2HCl
i think its 2NaOH + Cl2 ------------> NaClO + NaCl + H2O i think
The positive species which may attack on carbon or a pi bonds are electrophile as Cl+, NO2+ etc. but H+ and Positive metallic ions are not electrophile .
Hydrochloric acid and sodium hydroxide yield salt and water H+ + Cl- + Na+ + OH- --> Na+ + Cl- + H2OComment:In solutions you better leave unchanged ions ( Cl- and Na+) out of the balanced equation: called to be 'tribune ions' (people on the tribune don't take part in the 'match'):H+ + OH- --> H2O This looks simpler than: H+ + Cl - + Na + + OH- --> Na + + Cl - + H2O
Just replace one H and add a Cl (CH3Cl). In the next step replace another H by Cl. It's a chain reaction under sunlight: CH4+Cl2=CH3Cl+HCl CH3Cl+Cl2=CHCl2+HCL CH2Cl+Cl2=CHCl3+HCl CHCl3+Cl2=CCl4+HCl I'm sure now the structural formula will be apiece of cake.
H2 + Cl2 --> 2HCl Think of it like this. H2 begins with two electrons, Cl2 begins with 14 (it is diatomic and originally has 7 electrons, so 7 + 7 = 14). The reducing agent is the one being oxidized (you need to remember that!) and if something is being oxidized, it is going from having more electrons to less electrons. 2HCl has 16 electrons (where H has two and Cl has fourteen), so, unless there is a charge on any of these compounds that you did not include in your question, no, Cl is not the reducing agent.
H-H