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What is Kb for CH3NH2(aq) plus H2O(I) CH3NH3 plus (aq) plus OH-(aq)?
Kb = [CH3NH3 +] [OH-] / [CH3NH2]
Could KB for a weak base be determined the same way the Ka for a weak acid is determined?
cannot..because KB only can partially ionize to give OH+ while Ka only will partially ionize to give H+..
What do you get when you mix Pb plus 4 and OH-1?
You will get Pb(OH)4
In the reaction mgcl2 plus 2koh mg(oh)2 plus 2kcl How many moles are of mg(oh)2 are produced for every mole of mgcl2?
1
What happends to the OH- as the H plus increases?
The concentration of OH- decreases as the concentration of H+ increases. This is beacause there is an equilibrium H2O <-> H+ + OH- and therefore the [H+][OH-] is a constant
What is Kb for CH3NH2(aq) plus H2O(I) CH3NH3 plus (aq) plus OH-(aq)?
Kb = [CH3NH3 +] [OH-] / [CH3NH2]
What is KB for cn- aq h2o l hcn aq oh-aq?
Kb=[HCn][OH-] [CN-]
What is KB for c5h5n aq h2o l c5h5nh aq oh- aq?
kb=[C5H5NH+][OH-]______[C5H5N]
What is Kb for C5H5N(aq) H2O(l) C5H5NH (aq) OH-(aq)?
kb=[C5H5NH+][OH-]/[C5H5N]
What is Kb for CH3NH2(aq) H2O(l) CH3NH3 (aq) OH-(aq)?
Kb = [CH3NH3 +] [OH-] / [CH3NH2]
What is KB for cn aq h2o l hcn aq oh aq?
Kb=[HCN][OH-]/[CN-]
What is the KB expression for aniline?
The KB expression for aniline c6h5nh2 is: For C6H5NH2 + H2O >< C6H5NH3+ + OH-Kb = 4.3 x (10 ^ -10) = [C6H5NH3+][OH-] / [C6H5NH2]
What is KB for c5h5n aq h2o l c5h5nh aq oh aq?
Kb=c5h5nh+oh- / c5h5n (apex.)
What is the KB expression for aniline c6h5nh2?
The KB expression for aniline c6h5nh2 is: For C6H5NH2 + H2O >< C6H5NH3+ + OH-Kb = 4.3 x (10 ^ -10) = [C6H5NH3+][OH-] / [C6H5NH2]
What is KB equation for methylamine?
[ch3nh3+][oh-] / [ch3nh2]
What is Kb for (CH3)3N(aq) H2O(l) (CH3)3NH (aq) OH-(aq)?
Kb=[(Ch3)3 NH+][OH-]/[(Ch3)3 N]
What is KB for ch3 3n aq h2o l ch3 3nh aq oh-aq?
Kb=[(Ch3)3 NH+][OH-] __________ [(Ch3)3 N]
