keq= [SO2]2[O2]/[SO3]2
ALL THESE ARE WRONG! It's Keq = [so2]^2[o2]/[so3]^2
keq = [SO3]^2
---------
[SO2]^2[O2]
(apex)
At STP1mol O2 = 22.4L1mol O2 = 6.022 x 1023 molecules O222.4L O2 = 6.022 x 1023 molecules O2Convert liters O2 to moles O23.36L O2 X (6.022 x 1023 molecules O2/22.4L O2) = 9.03 x 1022 molecules O2
If the reaction is just between O2 and Al, the balanced equation would be:3O2 + 4Al -> 2Al2O3By using the coefficients of the equation, we see that from 3 moles of O2 we get 2 moles of Al2O3. To find out how much this is in grams, we need to find the molar mass of Al2O3 . This is just the sum of the atomic masses of each atom that makes it up. (Use a periodic table to find atomic masses) So we get:26.98*2+16*3= 102.0One mole equals 102g, so the 2 moles produced by the reaction would amount to 204g.
Yes, combustion is a chemical reaction, because it is a reaction between a molecule and oxygen (O2) to produce a new molecule plus CO2 (if it's a complete combustion) or CO (if it is an incomplete combustion). Combustion is also an exothermic reaction, which means that heat is released.
Typically nuclear reactions produce large amounts of energy.
Moles Mg = 3.00 g / 24.312 g/mol =0.123 Moles O2 = 2.20 / 32 g/mol = 0.0688 2 Mg + O2 >> 2 MgO the ratio between Mg and O2 is 2 : 1 0.123 / 2 = 0.0615 moles O2 needed we have 0.0688 moles of O2 so O2 is in excess and Mg is the limiting reactant we get 0.123 moles of MgO => 0.123 mol x 40.31 g/mol =4.96 g
keq=[SO3]2[O2] [So3]2
adding SO2
Not a combustion reaction. Combustion reactions produce CO2 and H2O.
4 atoms
SO2 + H20 --> H2SO3 sulphurous acid is not very stable though # The forest school, the forest school is wonderful the forest school is wonderful its filled with beer and Viagra the forest school is wonderful!!! #
Increase the concentration of SO2
K2CO3 (s) → K2O (s) + CO2 (g)2SO3 (g) → 2SO2 (g) + O2 (g) CaCO3 (s) → CaO (s) + O2 (g)
K2CO3 s -> K2O s plus CO2 g 2SO3 g -> 2SO2 g plus O2 g
Its balancing is very simple, 2SO2 + O2 = 2SO3
Sulphur burns in Oxygen to form Sulphur dioxide in the following reaction: S+O2=SO2 Sulphur dioxide has a capability of reacting with oxygen to form Sulphur trioxide in the following reaction: 2SO2+O2=2SO3 By Prince Sambo Metallurgist
2so2 + o2 ----> 2so3
2SO2(g) + O2(g) 2SO3(g)-The reverse reaction is favored.