The red color is RR and pink is Rr. RR is red, rr is white and Rr is pink. Cross the two: RR (red) and Rr (pink). You will get RR and Rr in a 1:1 ratio. You will not get any rr (white).The red color is RR and pink is Rr. RR is red, rr is white and Rr is pink. Cross the two: RR (red) and Rr (pink). You will get RR and Rr in a 1:1 ratio. You will not get any rr (white).
simple Mendelian genetics...right-handed is the dominant allele (R), left-handed is recessive (r). you can figure it out using a Punnett square. RR, Rr = RH kid rr = LH kid RR + RR = 100% RR -> all RH kids RR + Rr = 50% RR, 50% Rr -> all RH kids Rr + Rr = 25% RR, 50% Rr, 25% rr -> 75% RH kids, 25% LH kids rr + rr = 100% rr -> all LH kids to be LH, you have to have left-handedness somwhere in the family. however, you can be LH and neither your parents or grandparents would have to be.
RR x rr
R R r Rr Rr r Rr Rr That is the Punnet Square. The genotype will be 100% Rr in the cross. The phenotype will be whatever phenotype is constituted by your dominant allele.
what does r-r mean i mean rr
The red color is RR and pink is Rr. RR is red, rr is white and Rr is pink. Cross the two: RR (red) and Rr (pink). You will get RR and Rr in a 1:1 ratio. You will not get any rr (white).The red color is RR and pink is Rr. RR is red, rr is white and Rr is pink. Cross the two: RR (red) and Rr (pink). You will get RR and Rr in a 1:1 ratio. You will not get any rr (white).
Dihybrid cross
using a punnett square the parents would have to be Rr and rr
RR X rr 100% Rr Heterozygous resistant for poison ivy.
Rr X Rr = 1RR, 2 Rr, and 1rr
To figure this out, use a Punnet Square.First, set up a test cross, like this:Rr x rrThis shows what you are crossing. Now you can make a Punnet Square.R rr Rr rr There is a 50/50 chance that the corn plant will have thegenotype rr.r Rr rr
Rr
If they are expressing the trait, 100%, as their genotypes would be, rr X rr If they both carry the trait and it is dominated, Rr X Rr, then the probability would be, 25% of their child expressing the trait.
50%Rr to 50%rr
Make two punnett squares- one for Yy x YY and one for rr x RR the possible outcomes for Yy x YY are: YY Yy the only outcome for rr x RR is Rr. so the gametes of the two could be either YY Rr or Yy Rr
simple Mendelian genetics...right-handed is the dominant allele (R), left-handed is recessive (r). you can figure it out using a Punnett square. RR, Rr = RH kid rr = LH kid RR + RR = 100% RR -> all RH kids RR + Rr = 50% RR, 50% Rr -> all RH kids Rr + Rr = 25% RR, 50% Rr, 25% rr -> 75% RH kids, 25% LH kids rr + rr = 100% rr -> all LH kids to be LH, you have to have left-handedness somwhere in the family. however, you can be LH and neither your parents or grandparents would have to be.
RR x rr