The reaction is:
Po-210------------alpha particle------------------Pb-206
bismuth 210 decays by beta decay to polonium 210 that decays by alpha decay to lead 206
The correct equation for the alpha decay of Polonium-214 is: 218/84Po -> 214/82Pb + 4/2He This shows the decay of Polonium-214 into Lead-214 and a Helium nucleus, where the atomic number and mass numbers are conserved.
The equation for the alpha decay of 210Po is: 84210Po --> 82206Pb + 24He representing the alpha particle as a helium nucleus. 206Pb, the daughter atom, is stable.
Polonium-210 is an alpha emitter with a half-life of about 138 days. Its decay rate, or how fast it emits alpha particles, is a constant process determined by its decay constant, which is approximately 5.3 x 10^−9 per second.
Alpha decay is involved when polonium-214 decays into lead-210. In alpha decay, an alpha particle (2 protons and 2 neutrons) is emitted from the nucleus, reducing the atomic number by 2 and the mass number by 4.
Polonium-210 lose an alpha particle and become lead-206.
Polonium-210 is an alpha emitter.
The symbol Po-210 represents the radioactive isotope of polonium with an atomic number of 84 and a mass number of 210. Polonium-210 is a highly toxic substance that emits alpha particles during radioactive decay.
210 4 214 84 PO -------> 2 alpha + 86 RN
Polonium-210 decay to lead-206.
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
Polonium-218 undergoes alpha decay to form lead-214, which then undergoes beta decay to form bismuth-214.