For example a solution with the concentration of sodium chloride less than 10 g/L.
To prepare a 0.9% solution take 0.9grams NaCl and dilute with 100mls of water.
Dilute it.
Sodium hydroxide (NaOH) react with dilute Hydrochloric Acid (HCl) to form Sodium chloride (NaCl) and water (H2O).
Dilute Nitric acid when reacted with Sodium hydroxide will produce Sodium nitrate and Water. NaOH + HNO3 = NaNO3 + H2O.
No, the dilute solutions of highly water soluble compounds are unsaturatd as solution of NaCl but dilute solution of AgCl or BaSO4 are saturated because they are very little soluble in water.
Cl2 + 2NaOH ----> NaCl + NaClO + H2O or Cl2 + 2OH- ----> Cl- + ClO- + H2O
It will form salt sodium chloride and water (Nacl + H20)
By (internal) auto-redox reaction 'bleach' is formed: Cl2 + 2NaOH --> NaClO + NaCl
It means you dilute your sample in a volume that is as great as the one you current sample has. Ex: you dilute 50 ml NaCl-solution in 50 ml MQ-water. The result of this is that the concentration will always be halved, seeing as the volume increases twofold.
The reaction between HCl and NaOH is a neutralization reaction, or an acid/base reaction. It isHCl + NaOH ==> NaCl + H2O
You have to dilute the 10 mM NaCl 100X, 33,333X and 10X (X means "times") e.g. 100X: mix 10 ml of 10 mM Nacl with 990 ml of water (= 0,1 mM) 33,333X: mix 30 ml of 10 mM NaCl with 970 ml of water (= 0,3 mM) 10X: mix 100 ml of 10 mM NaCl with 900 ml of water (= 1 mM)
It could be done by electrolysis of a molten solution of NaCl, (not a dilute solution).