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Q: What is dynamic equilbrium of a saturated KCL solution?
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What mass of KCl would be needed to form a saturated solution if the KCl was dissolved in 200 g of water at 80 C?

Minimum 102,6 g of KCl.


How many moles of KCl are contained in 0.635L of 2.2M KCl?

moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl


Can KCl and CCl4 form a solution?

KCl and CCl4 do they form solution


How many moles of KCl are contained in 1.7L of a 0.83M KCl solution?

moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl


Why saturated KCL in DNA extraction is used?

Saturated KCl precipitation is often used in DNA extraction for molluscan taxa. Molluscs produce a polysaccharide rich mucus that interferes with the reagents involved in DNA extraction. The KCl saturated solution is used right after the digestion step: about 1/4th of the volume of the digestion solution is added to the sample. Samples are then centrifugated at 14rpm for 15 minutes. The pellet formed will contain the polysaccharides and non digested tissue. The supernatant is extracted from the tube and used in the next steps of the DNA extraction.


What volume of 0.060 M KCl solution contains 2.39g of KCl?

MW KCl = 74.6 g/mol2.39 gKCl * (1 mol KCL/74.6 g KCl)*(1 L solution/0.06 mol KCL) = 0.534 L


How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?

M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution


How will you prepare 3 liters of 2.5 M solution of KCl solution in water?

Dissolve 566.25g of KCl in 3L.


How much 75.66MKCL is required toprepare 1L of solution?

I did not know that you could get a concentration of 75.66 M KCl, but; Molarity = moles of solute/Liters of solution 75.66 M KCl = moles KCl/1 liter = 75.66 moles of KCl 75.66 moles KCl (74.55 grams/1 mole KCl) = 5640 grams KCl that is about 13 pounds of KCl in 1 liter of solution. This is why I think there is something really wrong with this problem!


How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?

Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed


How much KCL is required for 500mM KCL solution?

0.745*0.5 g


What is the molarity of a solution made by dissolving 4.88 g of KCl in 423 mL of solution?

Need mole KCl first. 4.88 grams KCl (1 mole KCl/74.55 grams) = 0.06546 moles KCl =======================now, Molarity = moles of solute/Liters of solution ( 423 ml = 0.423 Liters ) Molarity = 0.06546 moles KCl/0.423 Liters = 0.155 M KCl ------------------