mov
•The mov instruction carries out assignment in 8086 assembly language. •It which allows us place a number in a register or in a memory location (a variable) i.e. it assigns a value to a register or variable. Example: Store the ASCII code for the letter A in register bx.•A has ASCII code 65D (01000001B, 41H) •The following mov instruction carries out the task:•mov bx, 65d•We could also write it as:•mov bx, 41h•or mov bx, 01000001b•or mov bx, 'A'
mov r1r2 is invalid instruction because of there is no communication with ALU in its operation;
In 8086 the instruction queue is 6 byte long. This is because even the longest 8086 instruction is 6 byte long. Thus it is possible to prefetch even the longest instruction in the instruction set.
i.e.-->mov ax,2000h (in 8086)
mov H , L mov is opcode H L are operands
Mov ax,1234 mov bx,2345 add ax,bx mov @(some memory location ) say 2200,ax hlt
Mov ax,[2020h] mov bx,[2022h] mul bl mov [2024h],ax hlt
IRET
mov si,1300;source mov di.1500;destination mov ch,05;limit lo: mov al.[si] mov [di],al inc si inc di dec ch jnz lo
Code segment assume cs:code mov si,1500h mov di,1600h mov ax,[si] mov bx,[si+2] add ax,bx mov [di],ax mov [di+2],dx mov ah,4ch int 21h code ends end
1byte instruction = MOV A,B 2byte instruction = MVI A,01H 3byte instruction = STA 2030H