I do not see an isotope of iridium that does alpha decay. There is an interactive link to isotopes below. (Perhaps I am missing it.)
Iridium 192------beta particles----------Platinum 192
Iridium 192------electron capture------Osmium 192
Hal life: 73,827 days
78Pt192 ----> 76Os188 + 2He4
Plutonium-241 decays by both beta- and alpha decay. For beta- decay the equation is ...94241Pu -> 95241Am + e- + v-eNot asked but answered for completeness sake, for alpha decay the equation is ...94241Pu -> 92237U +24He2+
A:Uranium - 238 --> Pb - 206 + Alpha + Beta note this is a simplified over all reaction, the actual process involves around 15 steps...A:The equation for the alpha decay of 238U is: 92238U --> 90234Th + 24HeThe alpha particle is represented as an He nucleus.
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
There is no equation. Calcium-42 is stable and does not decay. Calcium is also much to light for alpha decay, which requires elements heavier than nickel, so no isotope of calcium undergoes alpha decay.
lithium
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
Uranium-239 does NOT decay by alpha decay, it decays only by beta and gammadecay.
92Au 282Xe +13S
The equation for the alpha decay of 213At: 85213At --> 83209Bi + 24He where the alpha particle is represented as a helium nucleus.
The equation for the alpha decay of 265Bh is:107265Bh --> 105261Db + 24He where the 24He is an alpha particle or helium nucleus.
78Pt192 ----> 76Os188 + 2He4
Plutonium-241 decays by both beta- and alpha decay. For beta- decay the equation is ...94241Pu -> 95241Am + e- + v-eNot asked but answered for completeness sake, for alpha decay the equation is ...94241Pu -> 92237U +24He2+
The equation for the alpha decay of 210Po is:84210Po --> 82206Pb + 24He where He represents the alpha particle, which can also be viewed as a Helium nucleus.
The first step is an alpha decay to (guess what!) uranium 235. You can probably take it from there.
Th-230(alpha)Ra-226.
The equation for the alpha decay of 233U is: 92233U --> 90229Th + 24He representing the alpha particle as a helium nucleus. 223U can also undergo fission, but since this is an rather unpredictable process, there is no standard equation.
The equation for the alpha decay of 235U is: 92235U --> 90231Th + 24He representing the alpha particle as a helium nucleus. 235U also decays by spontaneous fission, but the results are somewhat unpredictable, so there is no standard equation.