I do not see an isotope of iridium that does alpha decay. There is an interactive link to isotopes below. (Perhaps I am missing it.)
Iridium 192------beta particles----------Platinum 192
Iridium 192------electron capture------Osmium 192
Hal life: 73,827 days
78Pt192 ----> 76Os188 + 2He4
Plutonium-241 decays by both beta- and alpha decay. For beta- decay the equation is ...94241Pu -> 95241Am + e- + v-eNot asked but answered for completeness sake, for alpha decay the equation is ...94241Pu -> 92237U +24He2+
A:Uranium - 238 --> Pb - 206 + Alpha + Beta note this is a simplified over all reaction, the actual process involves around 15 steps...A:The equation for the alpha decay of 238U is: 92238U --> 90234Th + 24HeThe alpha particle is represented as an He nucleus.
There is no equation. Calcium-42 is stable and does not decay. Calcium is also much to light for alpha decay, which requires elements heavier than nickel, so no isotope of calcium undergoes alpha decay.
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
lithium
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
Uranium-239 does NOT decay by alpha decay, it decays only by beta and gammadecay.
92Au 282Xe +13S
The equation for the alpha decay of 213At: 85213At --> 83209Bi + 24He where the alpha particle is represented as a helium nucleus.
The equation for the alpha decay of 265Bh is:107265Bh --> 105261Db + 24He where the 24He is an alpha particle or helium nucleus.
78Pt192 ----> 76Os188 + 2He4
Plutonium-241 decays by both beta- and alpha decay. For beta- decay the equation is ...94241Pu -> 95241Am + e- + v-eNot asked but answered for completeness sake, for alpha decay the equation is ...94241Pu -> 92237U +24He2+
The equation for the alpha decay of 210Po is:84210Po --> 82206Pb + 24He where He represents the alpha particle, which can also be viewed as a Helium nucleus.
The first step is an alpha decay to (guess what!) uranium 235. You can probably take it from there.
Th-230(alpha)Ra-226.
The equation for the alpha decay of 233U is: 92233U --> 90229Th + 24He representing the alpha particle as a helium nucleus. 223U can also undergo fission, but since this is an rather unpredictable process, there is no standard equation.
The equation for the alpha decay of 235U is: 92235U --> 90231Th + 24He representing the alpha particle as a helium nucleus. 235U also decays by spontaneous fission, but the results are somewhat unpredictable, so there is no standard equation.