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A precipitate of Lead iodide and Potassium nitrate are formed
no
potassium nitrate would be left was an aqueous solution and lead iodide would be the precipitate
Pour a solution of Sodium(or Potassium) Iodide over Lead nitrate solution. The Lead iodide will be precipitated out as a yellow solid
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.
A yellow precipitate of silver iodide (AgI).
A precipitate of Lead iodide and Potassium nitrate are formed
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Ag(NO3)(aq) + KI(aq) ---> K(NO3)(aq) + AgI(s)
no
Lead iodide (Pb2I) precipitates as a yellow solid, leaving a solution of potassium and nitrate ions.
potassium nitrate would be left was an aqueous solution and lead iodide would be the precipitate
Pour a solution of Sodium(or Potassium) Iodide over Lead nitrate solution. The Lead iodide will be precipitated out as a yellow solid
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.
2KI+Pb(NO(3))(2) yields 2KNO(3)+PbI(2). You basically get potassium nitrate and lead (II) iodide when you react potassium iodide and lead nitrate dissolved in solution.
They form Silver Iodide and Poassium nitrate. Silver Iodide is a yellow coloured compound which forms precipitate in the solution. Potassium Nitrate remains dissolved. These reactions only take place in solution. When both reactants are in solid state then reaction may not occur, or it is too slow to be observed.
The products are Mercury(II) iodide and Potassium nitrate