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When to pee plants with T lower case Tt pollinated what Offspring will result?
When Tt plants (heterozygous for a trait) are pollinated, they can produce offspring with the genotypes TT, Tt, and tt. This follows the principles of Mendelian genetics, where the expected phenotypic ratio among the offspring would be 3:1 for dominant to recessive traits. Therefore, about 75% of the offspring will exhibit the dominant trait, while 25% will display the recessive trait.
When Mendel crossed short tt pea plants with short pea plants the offspring were?
When Mendel crossed short tt pea plants (homozygous recessive) with short pea plants that were heterozygous for height (Tt), the offspring would display a phenotypic ratio of 1 short (tt) to 1 tall (Tt). This is because the short plants (tt) can only contribute recessive alleles, while the heterozygous plants (Tt) can contribute either a dominant (T) or a recessive (t) allele. Therefore, half of the offspring would be tall and half would be short.
What is the importance of a 9331 ratio in a monohybrid cross?
The phenotypic ratio expected from a monohybrid cross between heterozygotes is 3:1 (assuming complete dominance), with the genotypic ratio being 1:2:1. So, using tall = T, short = t and R = red, r = white as an example. A monohybrid cross of Tt X Tt would be expected to produce 3 tall plants and 1 short plant (phenotypic ratio 3:1), which would be 1 TT, 2 Tt and 1 tt (genotypic ratio 1:2:1). A dihybrid cross of heterozygotes is expected to produce a phenotypic ratio of 9:3:3:1. So the cross of TtRr X TtRr would be epected to have: 9 tall red, 3 tall white, 3 short red and 1 short white (phenotypic ratio) This is because each parent has 4 possible combinations of gametes (TR, Tr, tR and tr). There are therefore 16 combinations of gametes, providing a 9:3:3:1 phenotypic ratio. Both of these are probably best visualised using a punnett square (see link below).
What are the genotype a of the parents?
genotype of the parents - parents will be heterozygous dominant. e.g. take the example of Mendel's pea cross. if parent is heterozygous dominant then the genotype will be Tt and Tt now if you will do a cross then the result you will get is this - Tt X Tt result - TT, Tt, Tt, tt it gives a 3 : 1 ratio i.e. three tall and one dwarf. Source: "tumul v" yahoo.answers
What will be the ratio produced if Tt is crossed with tt?
The ratio produced would be 1:1 for heterozygous (Tt) offspring to homozygous recessive (tt) offspring. This is because the parent with genotype Tt will pass on one dominant allele (T) and one recessive allele (t) to its offspring, resulting in a 50% chance of either genotype in the offspring.
What is the phenotypic ratio for Genotype TT Tt Tt tt?
3 : 1 ( since the given situation of segregating genotypes TT Tt Tt tt comes under monohybrid genetic combination, it will show 3 tall plants and 1 dwarf plant because gene T is dominant over t.
When to pee plants with T lower case Tt pollinated what Offspring will result?
When Tt plants (heterozygous for a trait) are pollinated, they can produce offspring with the genotypes TT, Tt, and tt. This follows the principles of Mendelian genetics, where the expected phenotypic ratio among the offspring would be 3:1 for dominant to recessive traits. Therefore, about 75% of the offspring will exhibit the dominant trait, while 25% will display the recessive trait.
Two individuals heterozygous for a single trait have children what is the expected phenotypic ratio of the possible offspring?
Let T=trait (dominant) Let t= trait (recessive) Father has Tt and mother also has Tt The possible combinations for offspring are: TT Tt Tt and tt Therefore There is a 3/4 change of the offspring having the dominant trait and a 1/4 Chance of the offspring having the recessive trait It should also be noted that there is a 1/4 chance of the offspring carrying two dominant genes meaning that any of their children will also share the dominant trait
What is the importance of a 9331 ratio in a monohybrid cross?
The phenotypic ratio expected from a monohybrid cross between heterozygotes is 3:1 (assuming complete dominance), with the genotypic ratio being 1:2:1. So, using tall = T, short = t and R = red, r = white as an example. A monohybrid cross of Tt X Tt would be expected to produce 3 tall plants and 1 short plant (phenotypic ratio 3:1), which would be 1 TT, 2 Tt and 1 tt (genotypic ratio 1:2:1). A dihybrid cross of heterozygotes is expected to produce a phenotypic ratio of 9:3:3:1. So the cross of TtRr X TtRr would be epected to have: 9 tall red, 3 tall white, 3 short red and 1 short white (phenotypic ratio) This is because each parent has 4 possible combinations of gametes (TR, Tr, tR and tr). There are therefore 16 combinations of gametes, providing a 9:3:3:1 phenotypic ratio. Both of these are probably best visualised using a punnett square (see link below).
If two heterozygous plants create four offspring how many do you predict would be tall?
Using a Punnett square, we can predict that 3 out of the 4 offspring will be tall if both parent plants are heterozygous for the tall trait (Tt x Tt). This is based on the 3:1 phenotypic ratio expected from a monohybrid cross.
Why was 3 1 the ratio in Mendels F2 generation?
In Mendel's F2 generation, the 3:1 ratio observed for dominant to recessive traits arises from the segregation of alleles during gamete formation. When he crossed heterozygous parents (Tt), the resulting offspring can inherit combinations of alleles that produce three dominant phenotype offspring (TT or Tt) and one recessive phenotype offspring (tt). This reflects the principles of Mendelian inheritance, specifically the law of segregation, where each parent contributes one allele for a trait, leading to the 3:1 phenotypic ratio in the F2 generation.
What are the genotype a of the parents?
genotype of the parents - parents will be heterozygous dominant. e.g. take the example of Mendel's pea cross. if parent is heterozygous dominant then the genotype will be Tt and Tt now if you will do a cross then the result you will get is this - Tt X Tt result - TT, Tt, Tt, tt it gives a 3 : 1 ratio i.e. three tall and one dwarf. Source: "tumul v" yahoo.answers
What will be the ratio produced if Tt is crossed with tt?
The ratio produced would be 1:1 for heterozygous (Tt) offspring to homozygous recessive (tt) offspring. This is because the parent with genotype Tt will pass on one dominant allele (T) and one recessive allele (t) to its offspring, resulting in a 50% chance of either genotype in the offspring.
What is the ratio produced if Tt is crossed with tt?
The ratio produced if Tt is crossed with tt is 1:1 for the genotype and 1:1 for the phenotype. This is because all the offspring will inherit a recessive allele from the tt parent, resulting in all of them having the same genotype and phenotype.
What are the possible offspring outcome if parent 1 Tt crosses with parent 2 tt tt?
Tt, tt -- novanet :)
What are the possible offspring outcomes if parent 1 Tt crosses with parent 2 tt?
The possible offspring outcomes of this cross would be 50% Tt (heterozygous) and 50% tt (homozygous recessive).
In the p generation a tall plant was crossed with a short plant. Short plants reappeared in the f2 generation because?
A cross between members of the F1 generation (Tt x Tt), results in the genotypic ratio of 1TT:2Tt:1tt genotypes in the F2 generation. Because the tall allele is dominant, the phenotypic ratio would be 3 tall:1 short in the F2 generation.
