Want this question answered?
Answer: 50% Tall : 50% Short
The phenotypic ratio expected from a monohybrid cross between heterozygotes is 3:1 (assuming complete dominance), with the genotypic ratio being 1:2:1. So, using tall = T, short = t and R = red, r = white as an example. A monohybrid cross of Tt X Tt would be expected to produce 3 tall plants and 1 short plant (phenotypic ratio 3:1), which would be 1 TT, 2 Tt and 1 tt (genotypic ratio 1:2:1). A dihybrid cross of heterozygotes is expected to produce a phenotypic ratio of 9:3:3:1. So the cross of TtRr X TtRr would be epected to have: 9 tall red, 3 tall white, 3 short red and 1 short white (phenotypic ratio) This is because each parent has 4 possible combinations of gametes (TR, Tr, tR and tr). There are therefore 16 combinations of gametes, providing a 9:3:3:1 phenotypic ratio. Both of these are probably best visualised using a punnett square (see link below).
genotype of the parents - parents will be heterozygous dominant. e.g. take the example of Mendel's pea cross. if parent is heterozygous dominant then the genotype will be Tt and Tt now if you will do a cross then the result you will get is this - Tt X Tt result - TT, Tt, Tt, tt it gives a 3 : 1 ratio i.e. three tall and one dwarf. Source: "tumul v" yahoo.answers
1/2 Tall 1/2 Short.
two capital or two lowercase letters in the GENOTYPE (ex: TT or tt) it's also called HOMOZYGOUS.
3 : 1 ( since the given situation of segregating genotypes TT Tt Tt tt comes under monohybrid genetic combination, it will show 3 tall plants and 1 dwarf plant because gene T is dominant over t.
Answer: 50% Tall : 50% Short
The phenotypic ratio expected from a monohybrid cross between heterozygotes is 3:1 (assuming complete dominance), with the genotypic ratio being 1:2:1. So, using tall = T, short = t and R = red, r = white as an example. A monohybrid cross of Tt X Tt would be expected to produce 3 tall plants and 1 short plant (phenotypic ratio 3:1), which would be 1 TT, 2 Tt and 1 tt (genotypic ratio 1:2:1). A dihybrid cross of heterozygotes is expected to produce a phenotypic ratio of 9:3:3:1. So the cross of TtRr X TtRr would be epected to have: 9 tall red, 3 tall white, 3 short red and 1 short white (phenotypic ratio) This is because each parent has 4 possible combinations of gametes (TR, Tr, tR and tr). There are therefore 16 combinations of gametes, providing a 9:3:3:1 phenotypic ratio. Both of these are probably best visualised using a punnett square (see link below).
genotype of the parents - parents will be heterozygous dominant. e.g. take the example of Mendel's pea cross. if parent is heterozygous dominant then the genotype will be Tt and Tt now if you will do a cross then the result you will get is this - Tt X Tt result - TT, Tt, Tt, tt it gives a 3 : 1 ratio i.e. three tall and one dwarf. Source: "tumul v" yahoo.answers
Let T=trait (dominant) Let t= trait (recessive) Father has Tt and mother also has Tt The possible combinations for offspring are: TT Tt Tt and tt Therefore There is a 3/4 change of the offspring having the dominant trait and a 1/4 Chance of the offspring having the recessive trait It should also be noted that there is a 1/4 chance of the offspring carrying two dominant genes meaning that any of their children will also share the dominant trait
A cross between members of the F1 generation (Tt x Tt), results in the genotypic ratio of 1TT:2Tt:1tt genotypes in the F2 generation. Because the tall allele is dominant, the phenotypic ratio would be 3 tall:1 short in the F2 generation.
Tt, tt -- novanet :)
1/2 Tall 1/2 Short.
If the two parent pea plants have Tt traits, they will create TT, Tt, Tt, tt. 1 TT - homozygous dominant, 2 Tt - heterozygous, and 1 tt - homozygous recessive.
A cross between members of the F1 generation (Tt x Tt), results in the genotypic ratio of 1TT:2Tt:1tt genotypes in the F2 generation. Because the tall allele is dominant, the phenotypic ratio would be 3 tall:1 short in the F2 generation.
Tt, tt -- novanet :)
TT Tt tt