lead II acetate and barium chloride equation
Perhaps a double replacement reaction? AB + CD --> AD + CB
2NaBr + Pb(NO3)2 --> PbBr2 + 2NaNO3
Barium chloride + lead II Nitrate = Lead Chloride + Barium Nitrate
Barium Chloride: BaCl2
Lead ii Nitrate: Pb(NO3)2
Barium Chloride + Lead ii Nitrate: PbCl2 + Ba(NO3)2
All elements are disassociated so there is no net Ionic equation
The net ionic equation for formation of a precipitate [note correct spelling] when sodium sulfate and barium chloride solutions are mixed is Ba+2 + SO4 -2 -> BaSO4 (s)
Barium Dichloride is NOT correct. The name is Barium Chloride it is a binary ionic compound.
Pb2+(aq)+2Cl-(aq)→PbCl2(s)
when barium chloride reacts with copper sulphate a double dispacement resction takes place,where: BaCl2(aq) + CuSO4(aq) --> BaSO4(s) + CuCl2(aq) The ionic equation is more descriptive: Ba2+ + 2Cl- + Cu2+ + SO4^2- --> BaSO4(s) + Cu2+ + 2Cl- The net ionic equation tells us that barium ions will always react with sulfate ions to make an insoluble product. Ba2+ + SO4^2- --> BaSO4(s)
All elements are disassociated so there is no net Ionic equation
Ionic
Copper nitrate and barium chloride do not react. Barium chloride solution produces a white precipitate with solutions containing sulfate ions.
The equation is:Ba+ + (SO4)2- = BaSO4(s)
The net ionic equation for formation of a precipitate [note correct spelling] when sodium sulfate and barium chloride solutions are mixed is Ba+2 + SO4 -2 -> BaSO4 (s)
Barium Dichloride is NOT correct. The name is Barium Chloride it is a binary ionic compound.
BaCl2 + CuSO4 = BaSO4 = CuCl2
Ba2+ (aq) + SO42- (aq) → BaSO4 (s)
Barium chloride is an ionic compound.
Pb2+(aq)+2Cl-(aq)→PbCl2(s)
Like all barium compounds it is ionic.
The formula for the ionic compound barium chloride is BaCl2.