Following is the Voltage calculation for a 3 Phase Full wave rectifier bridge circuit with 6 diodes:
Vac rms (Ph-Ph input) = 2pi / 3√2 x Vdc (output)
Vac rms (Ph-Ph input) = 0.74 x Vdc (output)
Hope that helps :)
Regards,
Syed
Percent ripple = (Vmax - Vmin)/Vmax
Vmax = (30.5)*(20.5)*VRMS
Vmin= 1.5*(20.5)*VRMS
A: THERE IS NO FORMULA it depends on the load and frequency and capacitance installed. Without those factors there is no formula to be applied.
The ripple factor of half wave rectifier is 1.21
0.4834 is the accurate ripple factor
It is not advisable to run lower voltage motor on a higher voltage.
because 3Phase power - V X I X Cos Phi X Square root of 3 and square root of 3 - 1.73
bcoz we dont require too much voltage when working in home so in home generally 220v is preferred & in industries 3phase connection is used for heavy loads (440v)
A 500 MCM copper conductor will limit the voltage drop to 3% or less when supplying 350 amps for 150 feet on a 208 volt system.
It would happen in case of 3phase domestic use where consumer side load balancing is not being done and there is loose connection in the neutral wire. Due to the unbalance and poor neutral, the system neutral will be shifted and un balanced voltages will be recorded in all the 3 phases of the house. The phase loaded with much utilities will indicate less voltage and other will have high voltage. Gadgets connected to this phase will be damaged.
It is not advisable to run lower voltage motor on a higher voltage.
This is a voltage drop question. A voltage must be stated to answer this question.
Generator coils generate the voltage, motor coils use the generated voltage.
It is possible to run a DC motor on a 3-phase supply using a full-wave rectifier if the voltage is right.
There is no 'total voltage' in a three-phase system. There are three line voltages and three phase voltages.
Ohm's Law - V = IR.
You can use either. I assume the 240 volts is the line to neutral voltage, and the 415 is the line to line voltages. They will both give you the correct answer. It is important to note these values are RMS, not 0 - peak voltages, but this may be beyond your question. The equations below are for calculated from RMS values (both voltage and current).If you are using a L-L voltage, P = I*V*sqrt(3)If you are using the L-N voltage, 1-phase power P = I*V (for the power in a single phase, for all three, multiply by 3), or 3phase power P = 3*I*VYou will get the same answer, since the L-N voltage is (1/sqr(3)) times the L-L voltage.
It depends on the voltage: 208 v 14 amps, 415 v 7 amps, 480 v 6 amps.
Take the current average of the three lines.Ex.Phase A = 10AmpsPhase B = 9 AmpsPhase C = 11 AmpsAverage = 10AmpsTake the voltage average of the three lines to ground,Phase A = 460VPhase B = 450VPhase C = 470VAverage 460VPower = V*I (Voltage times Current)Since we have a AC circuit,Power = V*I*1.732CommentUnfortunately, the above equation for power only works if you use line voltage; your explanation describes phase voltages. And, of course, it doesn't take power factor into account.
50 kVA is 16.667 kVA per phase and you divide that by the phase voltage. Current = 16667 / 277 = 60 Amps
depending on 1phase or 3phase voltage motor , the amphere requirement is found outfor 3phase AC motor use this formula: (HP x 746)/(1.73 x E x Eff x PF)for 1phase AC motor : (HP x 746) / (E x Eff x PF)
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