pH + pOH = 14.
So pOH = 14 - 1.12 = 12.88
pOH = -log[OH-]
[OH-] = 1.31 x 10-13 M
pH + pOH = 14
12.4 + pOH = 14
pOH = 1.6
pOH = -log[OH-]
1.6 = -log[OH-]
10-1.6 = [OH-] = 0.0251 M
To calculate the anticipated pH you need to have a balanced equation of your reaction, use the appropriate Ka or Kb values and determine the anticipated amount of excess ions and whether they are H+ or OH-. These will determine your pH.
How can you calculate pka valve if ph is given?
[OH-] = 3.31 log[OH-] = pOH = .51982 14-pOH = pH = 13.48
pH depends on ions H+ or OH-.
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Ist step, calculate pOH value by using formula pH + pOH = 14 2nd step, pOH = -log[OH], [OH] = - Antilog of pOH
The pOH is the negative log of the OH- concentration. Thus, pOH = -log 2.0x10^-2pOH = 1.699 = 1.7
To calculate the anticipated pH you need to have a balanced equation of your reaction, use the appropriate Ka or Kb values and determine the anticipated amount of excess ions and whether they are H+ or OH-. These will determine your pH.
There is no way to know the pH of sodium bicarbonate unless the concentration of [H+] or [OH-] is known. If the concentration is known, pH can be calculated as the -log[H+], or 14-(-log[OH-]).
Avicel pH 101 used in wet granultion and Avicel pH 112 is DC excipient.
pH, or power of Hydrogen, expresses concentration of H+ ions in a solutionm. As pure platinum would not have any H+ (nor OH-, for that matter) ions, it is not possible to calculate its pH.
little amount concentration of OH-...must afect the pH of this solution......so first u must calculate the concentration of oH-......& u must aply this fomula to culculate pOH(-log(oh-)......then pH+pOh is equal to 14 if temparature is 25 digree.....
HCl is a strong acid, so we assume that it completely breaks up into ions in solution. HCl ----> H+ & Cl- if we have 0.01m of HCl, it will give 0.01m of H+ and 0.01m Cl- pH = -log [H+] pH = -log 0.01 pH = 2
pH contribution only comes from dissociated H+ / OH- Common ion effect affects the kDiss calculation used to calculate the H+ conc
pH = - log [H+] Substitute and solve for [H+]: 7.5 = - log [H+] = 3.16E-8 That is the concentration of H+ ions. Depending on the acid, you calculate concentration of the acid based on this. Kw (dissociation constant) for water = 10^-14 Kw = [H+]*[OH-] Substitute and solve for the concentration of OH- = 3.16E-7 Depending on the base, you calculate the concentration of the base from this.
How can you calculate pka valve if ph is given?
[OH-] = 3.31 log[OH-] = pOH = .51982 14-pOH = pH = 13.48