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no wait sorry u find the number of moles N=Cv then compare them
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What is the OH- of a 4.0 x 10-4 M solution of CaOH2?
The concentration of the OH- is 8.0 x 10-4 In terms of molarity, since the hydroxide is double that of the calcium, double the molarity of the solution.
Mass of 24 mole of CaOH2?
1 mole of mass of ca (OH) 2 = 40*1 + (16 + 1) 2 = 40 + 34 = 74g. So, mass of 24 moles = 24*74 = 1776g.
What is the mass of CaOH2 required to have 10g of calcium?
m sub Ca(OH)2 = ( 10 g Ca ) [ ( 74.12 g Ca(OH)2 ) / ( 40.078 g Ca) ] m sub Ca(OH)2 = 18.5 g Ca(OH)2 <------------------
How many grams of CaOH2 are needed to prepare 300.0 mL of a 0.115 M solution?
Molarity = moles of solute/Liters of solution ( 300.0 ml = 0.300 liters ) ( Ca(OH)2 is correct formulation ) 0.115 M Ca(OH)2 = moles Ca(OH)2/0.300 Liters = 0.0345 moles Ca(OH)2 (74.096 grams/1 mole Ca(OH)2) = 2.56 grams of Ca(OH)2 needed
What is the pH of a solution in which OH equals 6.9 x 10 -10?
4.84
What is the OH- of a 4.0 x 10-4 M solution of CaOH2?
The concentration of the OH- is 8.0 x 10-4 In terms of molarity, since the hydroxide is double that of the calcium, double the molarity of the solution.
Mass of 24 mole of CaOH2?
1 mole of mass of ca (OH) 2 = 40*1 + (16 + 1) 2 = 40 + 34 = 74g. So, mass of 24 moles = 24*74 = 1776g.
What is the mass of CaOH2 required to have 10g of calcium?
m sub Ca(OH)2 = ( 10 g Ca ) [ ( 74.12 g Ca(OH)2 ) / ( 40.078 g Ca) ] m sub Ca(OH)2 = 18.5 g Ca(OH)2 <------------------
How many grams of CaOH2 are needed to prepare 300.0 mL of a 0.115 M solution?
Molarity = moles of solute/Liters of solution ( 300.0 ml = 0.300 liters ) ( Ca(OH)2 is correct formulation ) 0.115 M Ca(OH)2 = moles Ca(OH)2/0.300 Liters = 0.0345 moles Ca(OH)2 (74.096 grams/1 mole Ca(OH)2) = 2.56 grams of Ca(OH)2 needed
What would form an ionic bond N2O5 NCl3 CaOH2 Na2O?
Ca(OH)2 and Na2O
What is the mass of 7.346 moles of CaOH2?
The mass of 7,346 moles of Ca(OH)2 is 544,3 g.
How many moles of ions are in 2 moles of CaOH2?
2 moles of Ca and 4 moles of OH
Which of these solutions are acidic a solution with OH equals 2.5 10-9 H plus equals 1.2 10 -4 H plus equals 3.4 10-8 pH equals 4.5 OH equals 1.0 10-4?
solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
What is the pOH of a solution with a (OH-) of 10-2?
1.70
A solution has OH- 3.5 x 10-6 Based on that what must be true about this solution?
It is a basic solution.
A solution of NaOH has OH- 1.9 x 10-6 What is the pOH of this solution?
5.7
What is the pH of a solution with OH -?
Use this (at 25oC) : [OH-] = 10-(14-pH) ,so:[OH-] = 10-(14-5.75) = [OH-] = 10-8.25 = invlog(-8.25) = 5.6*10-9 mol/L
