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As far I know...Intel 8085 isz One address microprocessor.
The 8085 is an 8-bit microprocessor. Even though there are some 16-bit registers (BC, DE, HL, SP, PC), with some 16-bit operations that can be performed on them, and a 16-bit address bus, the accumulator (A), the arithmetic logic unit (ALU), and the data bus are 8-bits in size, making the 8085 an 8-bit computer.
8085 is a microprocessor designed by Intel
the 8085 microprocessor is a 8-bit microprocessor and these are bidirectional but the address lines are unidirectional.these address lines are used to address the location of the instruction in memory .these data lines are used to transfer data between processor and peripheral devices. when the address of the instruction will be recognized by the address lines the data will be send to the processor therefore the 16 address lines are not act as a data lines in 8085
Because that's how Intel designed it. The 8085 is an 8-bit computer operating on a 16-bit address space.
The '8085' in the 8085 microprocessor is the designation given to the microprocessor by Intel. The '5' means it is a single power supply (5 volt) version of the 8080, with enhancements.
+5v necessary for microprocessor 8085.
8085 is a 8 bit microprocessor designed by Intel Co.
The 8085 can address 216, or 65536 different memory locations.
with neat diagram explain the system bus structure of 8085
crystal is a oscilltor in microprocessor
The memory capacity of the 8085 microprocessor is 64 kb because the address bus is 16 bits, and you can address 216, or 64kb, with a 16 bit address bus.