The 8086 can address 1,114,080 bytes. (One Mb + 64Kb - 16) That does not count I/O space, it only counts memory space.
In 8086 pipeline concept was introduced bcoz in 8086 we started using a buffer space which fetches the instruction at the same time when CPU processes
There is no PC register in the 8086/8088. It is called the IP register by Intel and it stands for the Instruction Pointer. It contains the address of the current/next instruction to be executed.
The address bus in the 8085 is 16 bits wide.
Multiprocessors have a single physical address space (memory) shared by all the CPUs whereas multicomputers have one physical address space per CPU Multiprocessors have a single physical address space (memory) shared by all the CPUs whereas multicomputers have one physical address space per CPU
Physical address in the 8086/8088 is {Selected Segment Register} * 16 + {Effective Offset Address}. It is a 20-bit address .
The 8086/8088 has an internal 20-bit address bus and 16-bit data bus. Externally, the address bus is 20-bits, and the data bus is 16-bits for the 8086 and 8-bits for the 8088.The data bus in the 8086 is 16 bits in size, while the address bus is 20.
You can. There are thousands of microprocessors.
No. The 8086 has instructions not present in the 8085. The 8086 was marketed as "source compatible" with the 8085, meaning that there was a translator program which could convert assembly language code for the 8085 into assembly language code for the 8086. However, this does not mean that the compiled 8086 assembly code would then run on an 8085; among other things, the 8086 was a true 16-bit processor, as opposed to the 8085 which was an 8-bit processor that supported a few 16-bit operations.
Its role is to point to the next instruction to be executed in the CPU. It always points to the next instruction to be executed in the CPU
Effective address is the final address generated by offsetting and indexing which is sent to the virtual translation logic. It is the address of the operand in the virtual address space of the process, but not necessarily the address of the operand in the physical address space of the computer. In the 8085, efffective/virtual address is the same as physical address, because there is no virtual addressing logic in the 8085. In the 8086/8088, effective/virtual address is the same as physical address, but only in real mode. For example, in the 8086/8088, if the EBX register contains 1000000H, then the instruction MOV EAX,[EBX+1234H] has an effective address of 10001234H.
NONE! The 80186 was an advanced version of the 8086 but did not include support for virtual memory. It had a 64K physical address space. The 80286 was the first Intel CPU to support virtual memory but it's capabilities were limited.