6,8,7,9
2NH4Cl + Na2CO3 --> 2NH3 + CO2 + H2O + 2NaCl
Using the molar mass of nh3, we find that we have 2.5 moles of nh3. Since 3 moles of h2o are produced per 2 moles of nh3, we see that we will produce 3.75 moles of h2o. This is equivalent to around 3.79 g.
NH3 is a weak base (equilibrium more at the left than to the right side of the reaction equation: symbolized as <<==> ) NH3 + H2O <<==> NH4+ + OH-
NH4OH + HC2H3O2 ---> NH4C2H3O2 + H2ONH4+ + OH- + H+ + C2H3O2- ---> NH4+ + C2H3O2- + H2OOH- (aq) + H+ (aq)---> H2O (l)
2Fe3+ +2NH3OH --> 2Fe2+N2 + 2H2O + 4H+
2NH4Cl + Na2CO3 --> 2NH3 + CO2 + H2O + 2NaCl
Nh3 + h2o-----> nh4oh ----->(nh4)^+ + (oh)^-
1 nh3+ 2o2 >>>>> 1hno3 + 1h2o
NH4NO3 (aq) N2O (g) + 2H2O (l)
NH4OH < == > NH3 + H2O, it is a weak base
Using the molar mass of nh3, we find that we have 2.5 moles of nh3. Since 3 moles of h2o are produced per 2 moles of nh3, we see that we will produce 3.75 moles of h2o. This is equivalent to around 3.79 g.
The chemical reaction is: NH4NO3 + NaOH -----→ NH3 + H2O + NaNO3
NH3 is a weak base (equilibrium more at the left than to the right side of the reaction equation: symbolized as <<==> ) NH3 + H2O <<==> NH4+ + OH-
NH4OH + HC2H3O2 ---> NH4C2H3O2 + H2ONH4+ + OH- + H+ + C2H3O2- ---> NH4+ + C2H3O2- + H2OOH- (aq) + H+ (aq)---> H2O (l)
this is the balanced equation 4NH3 + 5O2 = 4NO + 6H2O
h2o
2Fe3+ +2NH3OH --> 2Fe2+N2 + 2H2O + 4H+