KOH + HNO3 --> KNO3 + H2O
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HNO3 + KOH ---> KNO3 + H2O
KNO3 and H2O are the products
It is a neutralization.KNO3 formed with water. KOH+HNO3 -->KNO3+H2O
Already balanced
Balanced :2 K + 2 H2O ----> 2 KOH + H2
HNO3 + KOH ---> KNO3 + H2O
KNO3 and H2O are the products
It is a neutralization.KNO3 formed with water. KOH+HNO3 -->KNO3+H2O
Potassium hydroxide and nitric acid will yield potassium nitrate and water. KOH + HNO3 --> H2O + KNO3
Since both the acid and the base have equivalent weights equal to their formula weights, 2 moles of KOH are needed to neutralize 2 moles of nitric acid.
Already balanced
Example:NH4OH + KNO3 -----------NH4NO3 + KOH
Balanced :2 K + 2 H2O ----> 2 KOH + H2
KOH(aq) + HNO3(aq) = KNO3(aq) + H2O(l)
HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Because HNO3 is a strong acid, when it combines with a strong base it will react. When you deal with a problem like this the positive ions, H+ and K+ switch places.
HNO3 + KOH -----> KNO3 + H2O
The reaction is:4KO2 + 2H2O ---> 4KOH + 3O2