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92Au 282Xe +13S
Th-230(alpha)Ra-226.
87Fr223 ----> 2He4 + 85At219
Po-216- -----------------> Pb-212
210 4 214 84 PO -------> 2 alpha + 86 RN
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
Uranium-239 does NOT decay by alpha decay, it decays only by beta and gammadecay.
92Au 282Xe +13S
The equation for the alpha decay of 213At: 85213At --> 83209Bi + 24He where the alpha particle is represented as a helium nucleus.
The equation for the alpha decay of 265Bh is:107265Bh --> 105261Db + 24He where the 24He is an alpha particle or helium nucleus.
Plutonium-241 decays by both beta- and alpha decay. For beta- decay the equation is ...94241Pu -> 95241Am + e- + v-eNot asked but answered for completeness sake, for alpha decay the equation is ...94241Pu -> 92237U +24He2+
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
The equation for the alpha decay of 210Po is:84210Po --> 82206Pb + 24He where He represents the alpha particle, which can also be viewed as a Helium nucleus.
The first step is an alpha decay to (guess what!) uranium 235. You can probably take it from there.
Th-230(alpha)Ra-226.
87Fr223 ----> 2He4 + 85At219
The equation for the alpha decay of 233U is: 92233U --> 90229Th + 24He representing the alpha particle as a helium nucleus. 223U can also undergo fission, but since this is an rather unpredictable process, there is no standard equation.