87Fr223 ----> 2He4 + 85At219
92Au 282Xe +13S
By alpha decay polonium-214 is transformed in lead-210. Po-214--------------alpha--------------Pb-210
Radon-198 does not decay via beta decay. It is thought to decay by alpha decay, but that is not certain. The equation would be ... 86198Rn -> (Alpha, T1/2 = 86 ms) -> 84194Po + 24He2+
Th-230(alpha)Ra-226.
The equation for the alpha decay of 210Po is: 84210Po --> 82206Pb + 24He representing the alpha particle as a helium nucleus. 206Pb, the daughter atom, is stable.
An alpha decay equation consists of the nucleus of an atom splitting into two parts: an alpha particle (He atom) and the resulting atom. To balance this equation, make sure that the amount of protons and neutrons are even on both sides.
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
Plutonium-241 decays by both beta- and alpha decay. For beta- decay the equation is ...94241Pu -> 95241Am + e- + v-eNot asked but answered for completeness sake, for alpha decay the equation is ...94241Pu -> 92237U +24He2+
The equation for the alpha decay of 233Pu:94233Pu --> 92229U + 24He2+where the alpha particle is represented as a helium nucleus.Note that 233Pu decays by alpha decay with a probability of only 0.12%. The other 99.88% is Beta+ decay.
Lead-210 decays by alpha or beta decay. The equation for the alpha decay of 210Pb is: 82210Pb --> 80206Hg + 24He representing the alpha particle as a helium nucleus. The equation for the beta decay of 210Pb is: 82210Pb --> 83210Bi + -10e where the -10e is an electron.
There is no equation. Calcium-42 is stable and does not decay. Calcium is also much to light for alpha decay, which requires elements heavier than nickel, so no isotope of calcium undergoes alpha decay.
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
Uranium-239 does NOT decay by alpha decay, it decays only by beta and gammadecay.
The equation for the alpha decay of 265Bh is:107265Bh --> 105261Db + 24He where the 24He is an alpha particle or helium nucleus.
The equation for the alpha decay of 213At: 85213At --> 83209Bi + 24He where the alpha particle is represented as a helium nucleus.
92Au 282Xe +13S
The equation for the alpha decay of 222Rn is: 86222Rn --> 84218Po + 24He Where He represents the alpha particle, which can also be viewed as a Helium nucleus.