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Coconut oil is a mixture, not a compound.
The general equation isCnH2n+2 + (1.5n+0.5)O2 -> nCO2 + (n+1)H2OTechnically, that's only really balanced for odd n; for even n you need to double it.
Cs2 + 3 o2 → co2 + 2 so2
2CoS(s) + 3O2(g) ----> 2CoO(s) + 2SO2(g)
1.3 g / 58.123 g C4H10 x -147.6 kJ =
C6H5CH=CH2: chemical formula: C8H8 Assuming no involvement of nitrogen: C8H8 + 10 O2 -> 8 CO2 + 4 H2O
YES!!! Providing it is combusted in oxygen(air( The reaction equation is 2H2(g)+ O2(g) = 2H2O(l)
18CO2 (g) +38HO2 (l)
C2H5OH +3O2 gives 2CO2 +3H2O ...it burns with ablue flame in air
This equation is C2H5OH + 3 O2 -> 2 CO2 + 3 H2O.
2 H2 + O2 = 2 H2O
Coconut oil is a mixture, not a compound.
If there is an excess of air, the reaction should produce diphosphorus pentoxide as its only product. If additionally the phosphorus molecule is simply a phosphorus atom, the balanced equation is: 4 P + 5 O2 -> 2P2O5. If phosphorus is considered to form a tetraatomic molecule, the equation would be: P4 + 5 O2 -> 2 P2O5
The combustion of hydrogen requires oxygen, which is supplied by the surrounding air. When hydrogen is combusted, it reacts with oxygen in the equation: 2H2 + O2 --> 2H2O with water (H2O) being the product
2Cu + O2 yields 2CuO
c12h26(i)--->c2h4(g)+______ Yuu shud work iht ouwt :)
O2(g)+2H2O(1)+4e---->4OH-(aq)