Oooh, this is a tricky one; as aluminum takes a 3+ charge and the sulphate (UK sulphate = USA sulfate!) a 2- negative. I think barium is 2+ (my chemistry was a while ago). My attempt would be:
Al2(SO4)3 + 3 Ba --> 3 BaSO4 + 2 Al
The reaction forms aluminum sulfate and frees copper.
no reaction between ammonium sulphate and iron sulphate
6co2+6h20+Light -> 6oc+c6h12o6Van Stevensvstevens90@gmail.com
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
Silver Chloride + Aluminum Nitrate. or AlCl3 + AgNO3 = Al(NO3)3 + AgCl (unbalanced)3AlCl3 + AgNO3 = Al(NO3)3 + 3AgCl (balanced)EDIT: I actually believe that the above equation is not balanced correctly.This is what I got;AlCl3 + 3AgNO3 = 3AgCl + Al(NO3)3
There is no reaction at all.
Al2(SO4)3 + 3Ca → 3CaSO4 + 2Al Aluminum sulfate + calcium → Calcium sulfate + aluminum
The chemical formula (not equation) of copper(II) sulfate is CuSO4.
2Al + 3CuSO4 = Al2(SO4)3 + 3Cu
2Al + 3CuSO4 = Al2(SO4)3 + 3Cu
The reaction forms aluminum sulfate and frees copper.
no reaction between ammonium sulphate and iron sulphate
Aluminium sulfate is soluble in water; no reaction occur.
Na2SO4 +CaCl2---------------> 2NaCL +CaSo4
6co2+6h20+Light -> 6oc+c6h12o6Van Stevensvstevens90@gmail.com
K2SO4(aq) + SrI2(aq)=SrSO4(aq) + 2kI(aq)
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4