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∙ 7y agoThe balanced equation for the reaction between phenol (C6H5OH), sodium hydroxide (NaOH), and iron(III) chloride (FeCl3) is:
C6H5OH + NaOH + FeCl3 → C6H4(OH)Na + FeCl2 + H2O
When sodium chloride reacts with ammonium hydroxide, it forms sodium hydroxide and ammonium chloride. The balanced chemical equation for this reaction is NaCl + NH4OH -> NaOH + NH4Cl. This is a double displacement reaction where the cations and anions of each compound switch partners.
The balanced chemical equation for the reaction between sodium hydroxide and copper(III) chloride is: 2NaOH + 3CuCl3 → 3Cu(OH)3 + 6NaCl This equation shows that two moles of sodium hydroxide react with three moles of copper(III) chloride to produce three moles of copper(III) hydroxide and six moles of sodium chloride.
The balanced equation for the reaction between sodium hydroxide and copper II chloride is: 2NaOH + CuCl2 -> 2NaCl + Cu(OH)2
When copper chloride is mixed with sodium hydroxide, a precipitation reaction occurs where solid copper(II) hydroxide is formed. The balanced chemical equation for this reaction is: CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl. This reaction is a double displacement reaction where copper ions and hydroxide ions switch partners to form the solid copper hydroxide.
The balanced equation for the reaction of stearic acid (C18H36O2) with sodium hydroxide (NaOH) is: C18H36O2 + 2NaOH -> C18H35O2Na + H2O.
Ferric Chloride = FeCl3Ammonium Hydroxide = NH4OHFerric (III) Chloride + Ammonium Hydroxide = Ferric (III) Hydroxide + Ammonium Chloride FeCl3 + 3NH4OH = Fe(OH)3 + 3NH4Cl
When sodium chloride reacts with ammonium hydroxide, it forms sodium hydroxide and ammonium chloride. The balanced chemical equation for this reaction is NaCl + NH4OH -> NaOH + NH4Cl. This is a double displacement reaction where the cations and anions of each compound switch partners.
The balanced chemical equation for the reaction between sodium hydroxide and copper(III) chloride is: 2NaOH + 3CuCl3 → 3Cu(OH)3 + 6NaCl This equation shows that two moles of sodium hydroxide react with three moles of copper(III) chloride to produce three moles of copper(III) hydroxide and six moles of sodium chloride.
The balanced equation for the reaction between sodium hydroxide and copper II chloride is: 2NaOH + CuCl2 -> 2NaCl + Cu(OH)2
When copper chloride is mixed with sodium hydroxide, a precipitation reaction occurs where solid copper(II) hydroxide is formed. The balanced chemical equation for this reaction is: CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl. This reaction is a double displacement reaction where copper ions and hydroxide ions switch partners to form the solid copper hydroxide.
The balanced equation for the reaction between calcium hydroxide and hydrochloric acid is: Ca(OH)2 + 2HCl → CaCl2 + 2H2O In this reaction, calcium hydroxide (Ca(OH)2) reacts with hydrochloric acid (HCl) to produce calcium chloride (CaCl2) and water (H2O). The equation is balanced with 1 molecule of calcium hydroxide reacting with 2 molecules of hydrochloric acid to produce 1 molecule of calcium chloride and 2 molecules of water.
The balanced equation for the reaction of stearic acid (C18H36O2) with sodium hydroxide (NaOH) is: C18H36O2 + 2NaOH -> C18H35O2Na + H2O.
Any reaction occur.
The reaction between sodium hydroxide and hydrochloric acid produces water and sodium chloride. The balanced chemical equation is: NaOH + HCl -> NaCl + H2O
The balanced equation for the reaction of sulfur trioxide with potassium hydroxide is: SO3 + 2KOH -> K2SO4 + H2O.
When ammonium chloride reacts with sodium hydroxide, it undergoes a double displacement reaction where ammonium chloride and sodium hydroxide switch partners to form ammonia, water, and sodium chloride. The balanced chemical equation for this reaction is NH4Cl + NaOH -> NH3 + H2O + NaCl.
When sodium hydroxide is added to ferrous chloride, a precipitation reaction occurs. This results in the formation of insoluble ferrous hydroxide, which appears as a greenish precipitate. The balanced equation for this reaction is: FeCl2 + 2NaOH → Fe(OH)2 + 2NaCl.