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The molecular equation is

6 I2 + 12 NaOH = 2 NaIO3 + 10 NaI + 6 H2O
and the net ionic is

6 I2 + 12 OH- = 2 IO3- + 10 I- + 6 H2O

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Q: What is the balanced equation of iodine reacting with sodium hydroxide?
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