2c4h10 + 13o2 => 8co2 + 10h2o
(I am having some trouble with my typography today, but all those letters above should be capitalized.)
The reaction is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
To balance the chemical equation C6H12O6 + O2 → CO2 + H2O: Start by balancing the carbon atoms by placing a coefficient of 6 in front of CO2. Balance the hydrogen atoms next by placing a coefficient of 6 in front of the H2O. Lastly, balance the oxygen atoms by placing a coefficient of 6 in front of O2 on the left side of the equation. The balanced equation is: C6H12O6 + 6 O2 → 6 CO2 + 6 H2O
28.76 g of O2 Write the complete combustion reaction and balance C3H8 + 5O2 yields 3CO2 + 4H2O set up ratio based on molar masses (stat organized) 44g = 160g X 7.91g Solve for X I have found this method easier for students (gen. chem) as compared to dimensional analysis
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
H2O (water), CO2 (carbon dioxide) and N2 (nitrogen) are chemical compounds. O2 (oxygen) is a diatomic molecule, not a compound.
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
To balance the combustion reaction of propane (C3H8), which produces carbon dioxide (CO2) and water (H2O), we start with the unbalanced equation: C3H8 + O2 → CO2 + H2O. Balancing it gives us: C3H8 + 5 O2 → 3 CO2 + 4 H2O. Therefore, the coefficient for O2 in the balanced equation is 5.
To balance the combustion reaction of propane (C3H8) with oxygen (O2), the equation starts as C3H8 + O2 → CO2 + H2O. After balancing, the coefficients for the reactants and products are C3H8 + 5 O2 → 3 CO2 + 4 H2O. Therefore, the coefficient for O2 in the balanced equation is 5.
5
5
C3H8 + O2 ---------> CO2 + H2O UNBALANCED C3H8 + 5O2 ---------> 3CO2 + 4H2O BALANCED
the answers is 6 _apex
The coefficient of O2 is 5.The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
C3h8 + 5o2 -> 3co2 + 4h2o
Study island answer: C3H8 + 5O2 3CO2 + 4H2O
If you mean the balanced reaction of the combustion of propane, it is: C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
The balanced chemical equation is C3H8 + 5 O2 ⟶ 3 CO2 + 4 H2O. This means that when one molecule of propane (C3H8) reacts with five molecules of oxygen (O2), it produces three molecules of carbon dioxide (CO2) and four molecules of water (H2O).