2c4h10 + 13o2 => 8co2 + 10h2o
(I am having some trouble with my typography today, but all those letters above should be capitalized.)
6.5
2c4h10 + 13o2 => 8co2 + 10h2o
(I am having some trouble with my typography today, but all those letters above should be capitalized.)
The balanced equation is 2C2H4O(g) + 5O2(g) ==> 4CO2(g) + 4H2O(g)So, the coefficient of O2 is 5.
C4H10 + O2 ------CO2 t H2O?
Ch=h+9h+w3=h6+45+c33
5
The reaction is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
Combustion Reactions are always reacted with Oxygen gas in this case if you had C3H8+O2 you will ALWAYS get H2O+CO2 it does not matter if you have C100H54+O2 you will still get H2O+CO2 this is why combustion reactions are considered exceptions to the rules of a product or chemical reaction.
co2 and h2o
CO2 and H2O
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
5
5
C3h8 + 5o2 -> 3co2 + 4h2o
The coefficient of O2 is 5.The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
The reaction is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
Study island answer: C3H8 + 5O2 3CO2 + 4H2O
If you mean the balanced reaction of the combustion of propane, it is: C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
the answers is 6 _apex
that is the equation for burning popane
The chemical reaction is: C3H8 + 5 O2 = 3 CO2 + 4 H2O
The balanced chemical equation for the combustion of propane is:C3H8 + 5O2 --> 3CO2 + 4H2O