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1/400 mho
Units are very important. I am assuming I = 0.04 [A]. If so, Ohm's Law says V = I * R = 0.04 * 100 = 4 [V]
The amount of heat something can dissipate into the air depends greatly on the size of it's surface area. This is why the thinner filament will burn more than the thicker part, because the thin part can not dissipate the heat as quickly. Filaments are in the past, get LED bulbs.
It would have a mechanical advantage of 20, thus dividing the resistance force of 600N by the effort force of 30N.
Use Ohm's Law - in this case, solving for current: I = V/R (current = voltage divided by resistance). Since you are using standard SI units, the answer will be in amperes.
25 ohmsAnswerResistance is measured in ohms. Conductance is measured in siemens. Conductance is the reciprocal of resistance. So the ohmic equivalent of 400 siemens is 2.5 milliohms.
1/400 mho
400 ohms
how much resistance must be connected in series with a 250 ohms inductive reactance to produce a total ciruit impedance of 400 ohms?
The resistance for 400 ft. of 10 AWG copper is .4 ohms. This would be a voltage drop of (.4 x 20) or 8 volts. For 120 VAC service this is a 6% which is a bit high. At 240 volts it is 3%. At 8 AWG the resistance is .251 ohms which will give you better performance.
The formula you are looking for is, R = Volts (squared)/Watts.
I believe the symbol you used, the "omega" stands for ohms, a measure of resistance in electricity and electrical work.
Line current = 10MW / 500kV = 20A Assuming the 1000 ohms is the resistance of the entire transmission line, end to end. Power loss = line current ^ 2 * line resistance = 20A ^ 2 * 1000 ohms = 400 KW
The resistance depends on how big the motor is. A small motor (less then 2-3 kW) , have greater resistance than a bigger one. Typically small motors have from 10 - 20 ohms to a few ohm. A 13 kWatt motor have typically 1-2 Ohm. A big 400 KWatt's motor have typically 10 milli ohms between the phases.
Eureka wire consists of Nickel 45% and Copper 55% . its operating temp. is 400 degreeC while melting point is 1270 degreeC.
10 AWG has a resistance of .1 ohms per 100 feet. As a rule of thumb you want less than a 10% drop in voltage because of wire. You use Ohm's Law to calculate the allowable drop. Volts = Amps x Resistance. The maximum amps for 10 AWG is 30 for typical household applications. So for example a 120 volt circuit could drop only 12 volts because of wire length (this is worse case) so R = 12/30 = .4 ohms. So dividing the .1 per 100 ft the result is 400 feet. For most applications I would recommend only about 250 ft.
I also have a '72 beetle - with a busted fuel sender unit. I have the installed one and another older one. They both have a floater attached to an arm that makes contact with resistance wire on the inside of the unit. The resistance wire is wrapped on the inside. So the resistance (and thus the voltage reading) changes as the contact (floater) moves. It seems that the delicate resistance wire is the weak point in the design and usually breaks. The contact part that brushes over the wire also sometimes can be a bit bent. If you can see the wire is broken you can try to replace the whole winding by removing the old and determining the value (in ohms/meter) and buying new resistance wire and rewinding it. Alternatively try and replace the whole resistance wire setup with a potentiometer (variable resistor) - I think that probably better. I actually got the old unit I had working this evening just to blow it up when I was clever enough to 'test' it with 12V without adding a current limiting resistor. before blowing it up I measured the resistance range: 0-400 ohms. the windings are regularly spaced, so the resistance should rise linearly with movement of the floater. I see if i can get anything fixed and let you know. Otherwise, if you live in USA try wolfsburgwest.com in Cali. they have new ones for $33. I live in South Africa :( - so I'll probably have to try and fix it or pay like more than double that.....