This enthalpy of reaction is 560 joules, for liquid water at 25 oC.
the reaction is from the combustion of Octane
Two moles of water are produced.
Sodium reacts with water. 0.652 NaOH moles will form.
2H2 + O2 ---------------> 2H2O for every 2 moles of hydrogen that reacts, 2 moles of water are produced, thus a 1:1 ratio of water produced to hydrogen reacted. So:- 2.5 moles of hydrogen reacted will produce 2.5 moles of water
The answer is: 5 moles oxygen and 4 moles H2O.The reaction is:C3H8 + 5 O2 = 3 CO2 + 4 H2O
During boiling the chemical composition is not changed.
The balanced equation for the synthesis of water from hydrogen and oxygen is: 2H2 + O2 --> 2H2O. If you have 1.4 moles of hydrogen, you will produce 1.4 moles of water because the molar ratio of hydrogen to water in this reaction is 2:2, which is the same as 1:1, which is the same as 1.4:1.4.
the reaction is from the combustion of Octane
In excess quantity of hydrogen (H2) 5.0 moles water can be formed maximally from 2.5 mole oxygen,because 2.5 x 2 (atoms O per mole oxygen, O2) = 5.0 x 1 (atoms O per mole water, H2O), thus balancing this reaction for oxygen atoms (5 on both sides).
This reaction?? 2H2O -> 2H2 + O2 this would be one to one and you would get; 174.82 moles of water vapor Without an equation I do not really know what you mean.
Two moles of water are produced.
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
It is a chemical change (reaction) because the chemical composition of the products (O2 and H2) is different from the chemical composition of the water (H2O).
Write out the equation first: 10H2 + 10O2 --> xH2O Since there are 2 moles of Hydrogen for every mole of Oxygen and equal moles of both are given, the Hydrogen limits the reaction as the limiting reactant. 10 moles of Hydrogen can make 10 moles of H2O with 5 moles of Oxygen left over. Think of it logically: H2 is two hydrogen atoms and water needs two hydrogen atoms, so it is a one-to-one reaction.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
Na +H2O -> NaOH +(1/2)H2 Every mole of Sodium requires one mole of water to make one mole of Sodium Hydroxide. So two moles of Sodium will produce two moles of Sodium Hydroxide. If there are three moles of water in the initial reaction then there will be one mole of water left over after reacting with two moles of Sodium. This reaction will produce half a mole of hydrogen gas.