Current I = V/R
V = 9V
R = 100ohm
I = 9V/100ohm = 90mA
No current flows through the battery. There is a current through the external circuit. I = E/R = 9/10 = 0.9 amperes.
Your current will be 30/R Amps. Where R is the resistance in Ohms.
A battery is rated to supply a certain number of volts. However, it actually supplies less, because they are "lost" as the current has to get out of the battery in the first place.(The battery has internal resistance)The amount of lost volts depends on the current being drawn:The less resistance a circuit has, the more current is drawn, because it's easier to flow.Example:If the circuit has little resistance, it draws a large current and the battery's internal resistance causes more lost volts.If the circuit has high resistance, it draws a small current and there are fewer lost volts.This is why when you short-circuit a battery (give it hardly any resistance to go through) it heats up and may explode. A large current is drawn and all the volts are used by the battery's internal resistance.
Ohms are the unit of measurement for resistance, so an ohmmeter is a device that measures electrical resistance. A galvanometer measures the current flowing through the resistance, so the two are related. To convert a galvanometer into an ohmmeter, one needs an external battery.
The heat produced due to electric current through a resistance is i) directly proportional to the square of the current ii) directly proportional to the resistance value of the conductor iii) directly proportional to the time of flow of current.
I=V/R Which means: amps(current) = voltage divided by resistance. 20= V/20
The formula you are looking for is R = E/I. Resistance is stated in ohms.
it determines how well the current flows through the wires. ANSWER: When there is no outside power connected to it. But some power is necessary to read the resistance so the meter battery will supply the current necessary to measure the IR drop and translate that to resistance
The resistance of a current is a measure of how difficult it is to push the electrons along.AnswerThere is no such thing as the 'resistance of a current'. Resistance is a characteristic of the material through which a current flows, not of the current itself.
V = IR Voltage = Current * Resistance so 9 = 0.25 * R Hence R =36 Ohms
The AVO has a battery in it. Some AVOs have a 1.5 v battery plus a 15 v battery, used for measuring large resistances. The battery pushes current through the resistor being tested, and the meter measures the current. Because the battery voltage varies, you have to set the zero-ohm point by adjusting a control each time a resistance measurement is done.
Ohm's Law: V = IR (voltage = current times resistance).Ohm's Law: V = IR (voltage = current times resistance).Ohm's Law: V = IR (voltage = current times resistance).Ohm's Law: V = IR (voltage = current times resistance).