Basically it is the difference between a quantity and a concentration. 0.5 mole HCl means approximately 17.73 gram of HCl. 0.50M HCl means that quantity of HCl per litre of solution.
So if you had two litre of 0.50M HCl solution, you would have 35.46 gram of HCl, but 0.5 mole HCl always means just 17.73 gram.
There are two other issues -- the first is an issue of precision. 0.5 mole in scientific practice means anything between 0.45 and 0.55 mole, that is (in this case) a ±10% margin of error. So 0.5 mole HCl might be anywhere between 16.0 and 19.5 gram. But 0.50M HCl is much more tightly constrained -- between 0.495 and 0.505 mole per litre, meaning between 17.55 and 17.91 gram per litre. The second is, of course, that with any chemical element whose symbol is 2 letters, like Cl, the second letter must be lower case -- Cl, not CL.
These chemicals react in a direct proportion of one to one, measured in moles of course, not by weight. A mole of NaOH weighs more than a mole of HCl.
The heat of neutralization between HCl and HNO3 is approximately -57.3 kJ/mol. This value is the heat released when one mole of HCl reacts with one mole of HNO3 to form one mole of water and one mole of the salt nitric acid (HNO3).
they both are same as HCl is a monobasic acid.>>>Not exactly. N stands for normal and M stands for mole. Knowing that, read this article to know the difference:http://answers.yahoo.com/question/index?qid=20070625100319AALNjoW
When HCl dissociates, it produces 1 mole of H+ ions and 1 mole of Cl- ions for every mole of HCl. So, 1 mole of HCl will produce a total of 2 moles of ions (H+ and Cl-).
0.1M HCl refers to a solution with a concentration of 0.1 moles of HCl per liter of solution, whereas 0.1N HCl refers to a solution with a normality of 0.1. Normality takes into account the chemical equivalent weight of a substance, so for HCl with a 1:1 mole ratio, the molarity and normality values would be the same.
These chemicals react in a direct proportion of one to one, measured in moles of course, not by weight. A mole of NaOH weighs more than a mole of HCl.
The heat of neutralization between HCl and HNO3 is approximately -57.3 kJ/mol. This value is the heat released when one mole of HCl reacts with one mole of HNO3 to form one mole of water and one mole of the salt nitric acid (HNO3).
they both are same as HCl is a monobasic acid.>>>Not exactly. N stands for normal and M stands for mole. Knowing that, read this article to know the difference:http://answers.yahoo.com/question/index?qid=20070625100319AALNjoW
When HCl dissociates, it produces 1 mole of H+ ions and 1 mole of Cl- ions for every mole of HCl. So, 1 mole of HCl will produce a total of 2 moles of ions (H+ and Cl-).
0.1M HCl refers to a solution with a concentration of 0.1 moles of HCl per liter of solution, whereas 0.1N HCl refers to a solution with a normality of 0.1. Normality takes into account the chemical equivalent weight of a substance, so for HCl with a 1:1 mole ratio, the molarity and normality values would be the same.
To find the mole fraction of HCl in the solution, we first need to calculate the molar mass of HCl (H=1g/mol, Cl=35.5g/mol). Then, determine the number of moles of HCl in 100g of the solution. Finally, calculate the mole fraction of HCl by dividing the moles of HCl by the total moles of solute and solvent in the solution.
The balanced chemical equation for the reaction between CuO and HCl is: CuO + 2HCl --> CuCl2 + H2O This equation shows that 1 mole of CuO reacts with 2 moles of HCl. Therefore, to react with 4 moles of HCl, you would need 2 moles of CuO.
Use grams to moles to moles to grams: 0.2 g of ammonia gas (NH3) is equivalent to 0.012 moles of NH3 (divide by 17g/mole) One mole of NH3 reacts with one mole of HCl: NH3 + HCl <=> NH4Cl So we need 0.012 moles of HCl to react with 0.012 moles of NH3 0.012 moles HCl * 36.5 g/mole HCl => 0.43 g HCl
2 HCl + CaCO3 -> CaCl2 + H2O + CO2 In words, two moles of hydrochloric acid reacts with one mole of calcium carbonate to yield one mole of calcium chloride, one mole of water, and one mole of carbon dioxide.
The spelling.
40 ml of NaOH contains 0.04 L * 3.5 M = 0.14 mole of NaOH Since NaOH donates 1 OH you will also have 0.14 mole of OH- in solution. This can be neutralised with an equal amount of H+. HCl can donate 1 H+, so you need an equal amount of H+ to neutralise the OH-. So you need 0.14 mole of the HCl. 55 ml has 0.14 mole HCl. So the molarity is: 0.14 mole / 0.055 L = 2.54 M
4 mole cuO X 2/1 = 8 mole Hcl