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sp3 is better

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Q: What is the difference between sp sp2 and sp3 hybridisations?
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Diffrence between sp2 and sp3?

SP3 has new updates already installed than SP2


What is the deferant between sp2 and sp3?

Service Pack 3 or (SP3) has more enhanced component compared to Service Pack 2 (SP2). Comments? Email at angelo.ment@gmail.com


How far apart are the sp3 orbitals in an sp hybridization?

Sp2 orbitals are used in the expansion of the molecules shape. The difference in distance between the Sp2 orbital in an SP hybridization is 120 degrees.


Why would you expect a C-C sigma bond formed by sp2-sp2 overlap to be stronger than a sigma bond formed by sp3-sp3 overlap?

because d c-c sigma bond formed by sp2-sp2 is formed from a double bond which is stronger than that of a single bond formed by sp3-sp3.


How many MB's is xp sp3 in windows update?

Depends. Windows requires that you have SP1 installed and recommends you have SP2 installed, but SP2 it is not necessary, in order to install SP3. So if you have just SP1 installed you are going to get SP2 and all subsequent updates along with SP3. If you have SP2 installed the SP3 update is around 16.1 MB. If you have only SP1 installed the download will be as much as 57.5 MB. It all depends on what you already have installed. I suggest you install SP2 before installing SP3. I also suggest you let Automatic Updates install this at a time when you are not on the computer. If you are on Dial-Up, order SP3 CD from Microsoft.


Should xp sp2 be uninstalled after installing xp sp3?

No.


What is the hybridization of SO32-?

Sp2....(due to two sigma bond with oxygen and a lone pair on sulphur.)


What covalent bonds can carbon form?

sp3,sp2,sp, these are covalent


What are the bond angles for sp3 single sp2 double and sp triple bonds?

The bonds angles are 109 degrees for an sp3 bond, 120 degrees for an sp2 bond, and 180 degrees for an sp bond.


What are the hybridization of the carbon atoms in CH3 CH2 COH?

The C in h3c is sp3 hybridized The c in ch is sp2 hybridized the c in ch2 is sp2 hybridized


Difference between sp2 and sp3?

The only difference I can think of is Security. I think the security will be much better so you don't get Spyware. I am downloading SP3 now, So if I find out after a while I will let you know-CodySP3 has new updates already installed than SP2SP3 has new updates already installed than SP2


Program for addition of two sparse matrix in 3 topule form?

// sparse matrix addition.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include<stdio.h> #include<conio.h> void read_sp_matrix(int sp[100][100]); void add_sp_matrix( int sp1[100][100],int sp2[100][100],int sp3[100][100]); void print_sp_matrix(int sp[100][100]); int _tmain(int argc, _TCHAR* argv[]) { int sp1[100][100],sp2[100][100],sp3[100][100],sp[100][100],i,j,k,r,c; printf("Enter the first sparse matrix row size,column size & number of non zero elements"); read_sp_matrix(sp1); printf("Enter the second sparse matrix row size,column size & number of non zero elements"); read_sp_matrix(sp2); printf("You entired the first sparse matrix \n"); print_sp_matrix(sp1); printf("You entired the second sparse matrix \n"); print_sp_matrix(sp2); printf("Result of sparse matrix addition \n"); add_sp_matrix(sp1,sp2,sp3); print_sp_matrix(sp3); getch(); } void read_sp_matrix(int sp[100][100]) { int i,j,k,r,c,t; scanf("d%d",&sp[0][0],&sp[0][1],&sp[0][2]); r=sp[0][0]; c=sp[0][1]; k=1; printf("Enter the sparse matrix elements \n"); for(i = 0; i < r; i++) { for(j = 0; j < c; j++) { scanf("%d",&t); if(t != 0) { sp[k][0] = i; sp[k][1] = j; sp[k][2] = t; k++; } } } } void add_sp_matrix(int sp1[100][100],int sp2[100][100],int sp3[100][100]) { int i,j,k,t1,t2,x; t1 = sp1[0][2]; t2 = sp2[0][2]; i=j=k=1; if((sp1[0][0] !=sp2[0][0])&&(sp1[0][1] !=sp2[0][1])) { printf("Invalid matrix ,try to correct \n"); goto x; } while((i <= t1)&&(j <= t2)) { if(sp1[i][0] < sp2[j][0]) { sp3[k][0] = sp1[i][0]; sp3[k][1] = sp1[i][1]; sp3[k][2] = sp1[i][2]; k++; i++; } else if(sp1[i][0] > sp2[j][0]) { sp3[k][0] = sp2[j][0]; sp3[k][1] = sp2[j][1]; sp3[k][2] = sp2[j][2]; k++; j++; } if((sp1[i][0] sp2[0][1]) { s = sp1[i][2] + sp2[j][2]; if(s != 0) { sp3[k][0] = sp1[i][0]; sp3[k][1] = sp1[i][1]; sp3[k][2] = sp1[i][2] + sp2[j][2]; k++; i++; j++; x++; } else { i++; j++; } } else if(sp1[i][1] > sp2[j][1]) { sp3[k][0] = sp2[j][0]; sp3[k][1] = sp2[j][1]; sp3[k][2] = sp2[j][2]; k++; j++; x++; } else { sp3[k][0] = sp1[i][0]; sp3[k][1] = sp1[i][1]; sp3[k][2] = sp1[i][2]; k++; i++; x++; } } else if(sp1[i][0] > sp2[j][0]) { sp3[k][0] = sp2[j][0]; sp3[k][1] = sp2[j][1]; sp3[k][2] = sp2[j][2]; k++; j++; x++; } else { sp3[k][0] = sp1[j][0]; sp3[k][1] = sp1[j][1]; sp3[k][2] = sp1[i][2]; k++; i++; x++; } } while(i <= t1) { sp3[k][0] = sp1[i][0]; sp3[k][1] = sp1[i][1]; sp3[k][2] = sp1[i][2]; k++; i++; x++; } while(j <= t2) { sp3[k][0] = sp2[j][0]; sp3[k][1] = sp2[j][1]; sp3[k][2] = sp2[j][2]; k++; j++; x++; } sp3[0][0] = sp1[0][0]; sp3[0][1] = sp1[0][1]; sp3[0][2] = x/*sp1[0][2]*/; int d = k-1; printf("The Resultant Matrix \n"); for(i= 0;i<=d;i++) { for(j=0;j<3;j++) { printf("%2d ",sp3[i][j]); } printf("\n"); } getch(); }