benzoic acid + hydroxide ion --> benzoate + water
benzoate is a benzene ring with a carbon branch double bonded to O and single bonded to O with a negative charge
I wish i could draw a picture... benzene ring ---C=O
O-
The reaction between ethanoic acid and sodium hydroxide forms Sodium acetate and Water.
CH3COOH + NaOH -----> CH3COONa + H2O
(Ethanoic acid) (Sodium hydroxide) (Sodium Acetate) (Water)
The chemical reaction between ethanoic acid plus sodium hydroxide is CH3COOH + NaOH -----> CH3COONa + H2O.
someone ans it plz plz plz smarty one not lala one
hai i just had this exact question and found it in my text book.
what you get is the Na bit goes onto the benzene bit so you get the benzene ring with COONa on it and the ethyl bit forms C2H5OH
:)
First: NaCO3 doesn't exist, it should be with sodium hydrogencarbonate or sodium carbonate
or
sodium hydroxide + propyl ethanoate --> propanoate ion + ethanoate.
This is a process called saponification, which is when an ester is catalyzed by a strong acid or alkali to produce a carboxylic acid and an alcohol and when in the presence of an alkali (sodium hydroxide in this case) the acid reacts with the alkali to form a carboxylate salt.
Saponification
Ester + hydroxide --> carboxylate ion + alcohol
benzoic acid + NaOH ---> water + sodium benzoate
HC7H5O2(aq) + NaOH(aq) ---> H2O(l) + NaC7H5O2
benzene-COOH + NaOH -> benzene-COO-Na + H2O
sodium ethoxide(NaOEt) and water are formed
C6H5COOH + NaOH ---> H2O + C6H5COO-Na+
No
yes.
what is the reaction of benzoic acid with sodium bicarbonate
benzoic acid + Sodium Hydroxide ==> water + sodium benzoate
just neutralized the benzoic acid by sodium hydroxide.....
Sodium benzoate is a salt of a weak acid (benzoic acid). In water, sodium benzoate hydrolyses to form a strong base (sodium hydroxide) and benzoinc acid. This is an equilibrium reaction. Benzoic acid being a weak acid is only partially ionized in water whilst sodium hydroxide is fully ionoized. The resultant solution is therefore alkaline since the concentration of hydroxyl ions is greater than the concentration of hydrogen ions. The addittion of hydrochloric acid results in an acid base reaction formating a salt (sodium chloride). Since the addition of hydrochloric acid removes the sodium hydroxide, it forces the equilibrium to the right forming more benzoic acid which is precipitated.
yes.
what is the reaction of benzoic acid with sodium bicarbonate
benzoic acid + Sodium Hydroxide ==> water + sodium benzoate
just neutralized the benzoic acid by sodium hydroxide.....
Sodium benzoate is a salt of a weak acid (benzoic acid). In water, sodium benzoate hydrolyses to form a strong base (sodium hydroxide) and benzoinc acid. This is an equilibrium reaction. Benzoic acid being a weak acid is only partially ionized in water whilst sodium hydroxide is fully ionoized. The resultant solution is therefore alkaline since the concentration of hydroxyl ions is greater than the concentration of hydrogen ions. The addittion of hydrochloric acid results in an acid base reaction formating a salt (sodium chloride). Since the addition of hydrochloric acid removes the sodium hydroxide, it forces the equilibrium to the right forming more benzoic acid which is precipitated.
There is no reaction. "Hydroxide acid" is water, which does not react with sodium hydroxide.
NO!!! They are two different chemicals. Sodium hydroxide is NaOH Sodium benzoate is ( C6H5)COO^-Na^+. It is the salt of benzoic acid.
It depends on the overall reaction. If the carboxylic acid is an impurity in the reaction (undesired), then washing with sodium hydroxide will extract the carboxylic into the aqueous layer, and it can then be disposed. The reaction for this looks as follows: (ring)-COOH + NaOH -> (ring)-COO-Na+ + H20 Where the ring loses a proton to the hydroxide ion and becomes water soluble.
CH3cooh + NAHCO3
Sodium benzoate is manufactured by reacting benzoic acid with sodium hydroxide. Benzoic acid is produced by partial oxydation of toluene with oxygen. There are half a dozen ways or more ways to make toluene.
The reaction is the following:Mg(OH)2 + 2 C6H5COOH = Mg(C6H5COO)2 + 2 H2O
C6H5COOH + NaHCO3 ===> C6H5COO-Na+ + H2O + CO2