Chemistry

# What is the final molarity of 5.84 grams of Na Cl?

###### Wiki User

Depending on the volume of water ! For 1 L, the molarity is approx. 0,1.

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## Related Questions

Molarity = moles of solute/Liters of solution Find moles NaCl 9 grams NaCl (1 mole NaCl/58.44 grams) = 0.154 moles NaCl Molarity = 0.154 moles NaCl/1 Liter = 0.2 M sodium chloride -------------------------------

Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------

You need to have the weight per litre so you multiply by 4. 19.55x4 is 78.2 grams per litre. 78.2 divided by 58.443g/mol is 1.338 molar.

That is approximately 450 grams of water

7.7 X 1012 atoms Cl (1 mole Cl/6.022 X 1023)(35.45 grams/1 mole Cl) = 4.5 X 10 -10 grams of chlorine -----------------------------------------

3.01 X 1023 atoms of chlorine (1 mole Cl/6.022 X 1023)(35.45 grams/1 mole Cl) = 17.7 grams of chlorine ======================as indicated, half of Avogadro's number yields half the mass

It is 0.22M also. moles refers to an amount of molecules OR atoms (i.e. ions)

One mole of KCl is (39.1 grams K) + (35.5 grams Cl) = 74.6 grams

Balanced equation. 2Na + Cl2 &gt;&gt; 2NaCl 46 grams sodium = 2 mol 23 grams Chlorine = 0.65 mol ( I think Chlorine is limiting ) 0.65 mol Cl (2mol Na/1mol Cl ) = 1.3 mol ( you do not have that; Cl limits ) 0.65 mol Cl (2mol NaCl/1mol Cl2 )(58.44g/1mol NaCl ) = 75.9 grams

Balanced equation. 2K + Cl2 &gt;&gt; 2KCl 39 grams K (1mol K/39.10g )(1mol Cl/2mol K )(35.45g/1 mol Cl ) = 17.7 grams

2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)

Silver chloride: AgClAtomic mass of Ag: 107.9 gramsAtomic mass of Cl: 35.5 gramsMolecular mass: 107.9 + 35.5 = 143.4 grams107.9 grams Ag / 143.4 grams AgCl = .75235.5 grams Cl / 143.3 grams AgCl = .248Take the results and multiply by 100 to change to a percent:.752 &Atilde;&mdash; 100 = 75.2% Ag.248 &Atilde;&mdash; 100 = 24.8% Cl

58 g NaCl = 58 (g) / 58.44 (g/mol NaCl) = 0.9925 (mol NaCl) = 0.9925 (mol Cl-) = 0.9925 * 35.45 (g/mol Cl-) = 35.2 g Cl-

Molarity means moles per litre. So if you have 2 litres divide the moles by 2. 6/2 is 3 moles per litre or 3M.

Silver chloride - AgClAg (107.89 grams) + Cl (35.45 grams) = 143.34 grams

There would be 117g of NaCl in 1000 ml or 1 liter. The MWt of NaCl is 58.5 so 117/58.5 is 2.00 - so the molarity is 2.00 moles per liter of NaCl

1.409 moles chlorine (35.45 grams/1 mole Cl) = 49.95 grams of chlorine ==================

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