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Answered 2012-04-01 20:21:23
Depending on the volume of water ! For 1 L, the molarity is approx. 0,1.
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Molarity = moles of solute/Liters of solution Find moles NaCl 9 grams NaCl (1 mole NaCl/58.44 grams) = 0.154 moles NaCl Molarity = 0.154 moles NaCl/1 Liter = 0.2 M sodium chloride -------------------------------
what is 15 cl in grams
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
About 188.2 grams of Cl.
You need to have the weight per litre so you multiply by 4. 19.55x4 is 78.2 grams per litre. 78.2 divided by 58.443g/mol is 1.338 molar.
The answer is 45,776 grams.
That is approximately 450 grams of water
it's 63.89% Cl. that % of 115g is 73.47g
7.7 X 1012 atoms Cl (1 mole Cl/6.022 X 1023)(35.45 grams/1 mole Cl) = 4.5 X 10 -10 grams of chlorine -----------------------------------------
3.01 X 1023 atoms of chlorine (1 mole Cl/6.022 X 1023)(35.45 grams/1 mole Cl) = 17.7 grams of chlorine ======================as indicated, half of Avogadro's number yields half the mass
365 grams of CaCl2 contain 232,27 g chlorine.
It is 0.22M also. moles refers to an amount of molecules OR atoms (i.e. ions)
125 g CaCl2 contain 79,54 g Cl.
One mole of KCl is (39.1 grams K) + (35.5 grams Cl) = 74.6 grams
Balanced equation. 2Na + Cl2 >> 2NaCl 46 grams sodium = 2 mol 23 grams Chlorine = 0.65 mol ( I think Chlorine is limiting ) 0.65 mol Cl (2mol Na/1mol Cl ) = 1.3 mol ( you do not have that; Cl limits ) 0.65 mol Cl (2mol NaCl/1mol Cl2 )(58.44g/1mol NaCl ) = 75.9 grams
Balanced equation. 2K + Cl2 >> 2KCl 39 grams K (1mol K/39.10g )(1mol Cl/2mol K )(35.45g/1 mol Cl ) = 17.7 grams
10.0gCl*1 mole Cl*22.4Cl L/ 35.45g Cl* 1mole Cl=6.32L Cl
2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)
Silver chloride: AgClAtomic mass of Ag: 107.9 gramsAtomic mass of Cl: 35.5 gramsMolecular mass: 107.9 + 35.5 = 143.4 grams107.9 grams Ag / 143.4 grams AgCl = .75235.5 grams Cl / 143.3 grams AgCl = .248Take the results and multiply by 100 to change to a percent:.752 × 100 = 75.2% Ag.248 × 100 = 24.8% Cl
58 g NaCl = 58 (g) / 58.44 (g/mol NaCl) = 0.9925 (mol NaCl) = 0.9925 (mol Cl-) = 0.9925 * 35.45 (g/mol Cl-) = 35.2 g Cl-
Molarity means moles per litre. So if you have 2 litres divide the moles by 2. 6/2 is 3 moles per litre or 3M.
Silver chloride - AgClAg (107.89 grams) + Cl (35.45 grams) = 143.34 grams
80g approx, if the density = 1
There would be 117g of NaCl in 1000 ml or 1 liter. The MWt of NaCl is 58.5 so 117/58.5 is 2.00 - so the molarity is 2.00 moles per liter of NaCl
1.409 moles chlorine (35.45 grams/1 mole Cl) = 49.95 grams of chlorine ==================
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