Depending on the volume of water ! For 1 L, the molarity is approx. 0,1.
Molarity= moles/Liters To change grams to moles you divide by the mole weight which is listed on the periodic table. Mol= grams/mol weight The Mole weight of Magnesium Chloride is 59.8 grams/mol Mol=128g/59.8 Mol=2.14 Now, you put the number of moles and Liters into the equation Molarity=2.14 mol/1L Molarity=2.14 So, the molarity is 2.14 M
To find the molarity of Cl in the solution, first calculate the number of moles of CaCl2 using its molar mass. Then, since each formula unit of CaCl2 contains 2 moles of Cl, multiply the moles of CaCl2 by 2 to get moles of Cl. Finally, divide moles of Cl by the volume of the solution in liters to find the molarity.
It is 0.22M also. moles refers to an amount of molecules OR atoms (i.e. ions)
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
To calculate molarity, first find the moles of the solute (NaCl) using its molar mass. The molar mass of NaCl is 58.44 g/mol (Na=22.99 g/mol, Cl=35.45 g/mol). Divide the mass of NaCl (19.55 g) by its molar mass to get moles. Then, divide the moles by the volume of solution in liters (0.25 L) to find the molarity.
A centiliter (cl) is equivalent to 10 milliliters (ml), and the weight in grams of a substance in a cl jar depends on its density. For water, 1 cl is approximately 10 grams. Therefore, the number of grams in a cl jar will vary based on the density of the substance stored in it.
To determine the mass of AgCl needed, first calculate the number of moles needed using the molarity equation: moles = molarity x volume (in L). Then, convert moles of AgCl to grams by using the molar mass of AgCl (107.87 g/mol for Ag and 35.45 g/mol for Cl). Finally, perform the calculation to find the grams of AgCl required.
15cL equals 0.15L* There are 100cL per liter
1.0 mL of water
To find the mass of 64 moles of Cl (chlorine), you need to multiply the number of moles by the molar mass of Cl. The molar mass of Cl is approximately 35.45 g/mol. Therefore, 64 moles of Cl would be approximately 2267.2 grams (64 moles x 35.45 g/mol).
Balanced equation. 2K + Cl2 >> 2KCl 39 grams K (1mol K/39.10g )(1mol Cl/2mol K )(35.45g/1 mol Cl ) = 17.7 grams
To calculate the molarity of the solution, we first need to determine the number of moles of NaCl in 400 mg. The molar mass of NaCl is approximately 58.44 g/mol. Converting 400 mg to grams gives us 0.4 g. Dividing this by the molar mass gives us approximately 0.0068 moles of NaCl. Since the volume is 100 mL or 0.1 L, the molarity is calculated as moles divided by liters, giving us approximately 0.068 M.