0
What is the final temperature of 25.0 grams of water at 22.0 and 8728C after it absorbs 124J of heat?
Wiki User
∙ 7y ago
875J/12.6g*4.18Jg-1°C+22.9°C=39.5°C
Wiki User
∙ 10y ago
Add your answer:
Earn +20 pts
What will the final temperature be if 688 calories of heat is released by 25 mL of water with an initial temperature of 80 degrees celsius?
Do some converting first. 688 calories (4.184 Joules/1 calorie) = 2878.592 Joules 25 ml of water = 25 grams q(Jolules) = mass * specific heat * (Temp. final - Temp. initial) 2878.592 Joules = 25 grams Water * 4.180 J/gC * (Temp Final - 80C ) 2878.592 Joiles = 104.5( Temp. Final) - 8360 11238.592 =104.5(Temp. Final) 107.55 Celsius Final Temperature ( call it 108 C )
How many grams weighs 850 mL of water?
For pure clean water at standard temperature and pressure, 850 ml has a mass of 850 grams.
Is gram used to measure the temperature in the metric system?
No, grams are unit of mass, not temperature. Temperature is measured in °C (degrees celsius) or for scientific work in 'K' K = °C + 273.15
How do you convert 1.42 kg to moles?
You have to first convert Kilos to grams. 1.42 kilos is 1420 grams. Next you have to find out the molecular weight (can be added up from the periodic table). Now divide grams by molecular weight to get your final answer in moles.
A beaker containing 80 grams of KNO3 in 100 grams of water have a temperature of 30 and Acirc and degC. Approximately how many grams of the salt are undissolved on the bottom of the beaker?
The mass of undissolved potassium nitrate is cca. 3 g.
If 75 grams of water at 30 degrees Celsius absorbs 900 calories what will be the new temperature?
105C
What would be the final temperature when 250 grams of water at 100 degrees celsius is mixed with 525 grams of water at 30 degrees celsius?
The temperature would be that of water's boilng point od 100 degrees
When 418 joules of heat energy are added to 10 grams of water at 20C the final temperature of the water will be?
21
What will the final temperature be if 688 calories of heat is released by 25 mL of water with an initial temperature of 80 degrees celsius?
Do some converting first. 688 calories (4.184 Joules/1 calorie) = 2878.592 Joules 25 ml of water = 25 grams q(Jolules) = mass * specific heat * (Temp. final - Temp. initial) 2878.592 Joules = 25 grams Water * 4.180 J/gC * (Temp Final - 80C ) 2878.592 Joiles = 104.5( Temp. Final) - 8360 11238.592 =104.5(Temp. Final) 107.55 Celsius Final Temperature ( call it 108 C )
What is the final temperature of the mixture if 100gram of water at 70temperature is added to 200gram of cold water at 10temperature and well stirred?
I'll assume here that by "70 temperature" you mean "70 degrees Celsius". Basically, you have to calculate the average temperature of all of the water in the mixture, which will be the final temperature once it's well stirred. The 200 grams of water at 10 degrees represent 2/3 of the total amount of water (300 grams), so thus, multiply 10 by 2/3 to determine their contribution to the final temperature. You will get 20/3. The 100 grams of water at 70 degrees represent 1/3 of the total amount of water, so multiply 70 by 1/3 to determine their contribution to the final temperature. You will get 70/3. When you add together the two temperatures you get 90/3, which is equal to 30. Therefore, the final temperature is 30 degrees Celsius.
What is a specific heat for a metal sample with a mass of g which absorbs J of energy when its temperature increases from 30.0 Celsius to 98.0 Celsius?
specific heat = absorbed heat/mass.68
What is the unit to temperature?
Grams
One hundred twenty grams of metal at 88 degree Celsius is poured into a 70 grams insulated cup contains 250 grams of water at 16 degree Celsius.The final temperature of the mixture is 17.5 degree celc?
It is not possible to answer the question without information about the specific heat of the metal and of the cup.
How many grams water are in 100 milliliters of water?
The answer depends on the temperature, but at room temperature (20 deg C), 100 ml of water would have a mass of 99.82 grams.
How many grams of sodium nitrate can be dissolved in 100 grams of water at a temperature of 50C?
114g
What is the amount of heat required to change the temperature of 200.0 grams of aluminium to 10 degrees Celsius?
Q=m.c.Δt (m: mass, c: specific heat capacity, Δt :change in temperature)(specific heat capacity of aliminum is 0.90 J/K.g = 200 x 0.90 x 10 (if initial temperature is 0)(if not, then Δt=final temperature-initial temperature) =1800 Joules
What is the final equilibrium temperature when 15 grams of milk at 22 degrees Celsius is added to 185 grams of coffee at 86 degrees Celsius?
If coffee and milk have the same thermal coefficient then: (15*22 + 185*86)/200 = 81 (81,2 rounded off due to significant digits)
