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15.37684 joules
15480.80
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
21 grams through 71 degrees is 21x71 calories.
I assume you mean 30o Celsius. Use this formula.q(joules) = mass * specific heat * change in temperatureq = (15 grams water)(4.180 J/gC)(40o C - 30o C)= 627 joules==========( perhaps 630 joules to be in significant figures territory )
The amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy is 42,2g H2O.
15.37684 joules
8.200 J
Temperature is measured in celcius.Heat is measured in joules.
Approx 4974 Joules.
There is not enough information in this problem to answer the question. You must know the mass of the iron to find the amount of joules used to heat the iron.
15480.80
The answer is 53,683 kJ.
10 degrees Celsius
It take 4.2 Joules to raise 1 gram of water by 1 degree Celsius. Each gram of water is heated by 1.26 Joules, creating an increase in temperature of .3 degrees Celsius.
3.8 x 10^5 Joules
The change in temperature is 25 degrees Celsius, meaning it takes 22.48 joules per degree of change. The specific heat of iron is 0.449 J/g degree Celsius. This means that the mass of iron must be 50.07 grams