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Is this question referring to the MASS of the car pushing DOWN on the road?
Assume: the typical 4 door sedan weight about 1.5 tons (3000 pounds = 1360.7kg)
Earth's gravity = 9.8m/s^2 acceleration. Then use the formula Force = mass X acceleration (F=MA) or 1360.7kg X 9.8m/s^2 = 13,334.86 Newtons downwards (here as a "kilogram-force")
OR is the question asking how much force a moving car would have on a (nonmoving) object should it impact?
Assume same vehicle dimensions and said vehicle is traveling at 60mph (= 1 mile per minute = 88 feet per second = 26.82 meters per second).
Next assumption: The car came to a COMPLETE stop (quick deceleration= crash) in about 16 feet or 5 meters and this happened in 1/2 a second or 500 milliseconds.
The deceleration is 26.83m/s to zero in 500 milliseconds
Vf-Vo= 0- 26.83 divided by (change in time) = .5 seconds = -53.66 m/s^2
So 1360.7 kg times -(neg) 53.66 m/s^2 = 73015.16 Newtons or 16414.461 pounds.
In summary, the force applied in a "crash" (aka rapid deceleration) is about 5.5 times the weight of the car in this example.
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∙ 13y ago
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