Empirical formula = C3H5O Molar mass of empirical formula = 3(12.01)+5(1.008)+1(16) = 57.07 Molar mass of molecular fomula = 114.15 n = Molar mass of molecular fomula/Molar mass of empirical formula = 114.15/57.07 n = 2 Molecular formula = n(empirical formula) Molecular formula = 2(C3H5O) = C6H10O2 Check: 6(12.01)+10(1.008)+2(16)= 114.14
Barium is in Group 2, so we know that it makes 2+ ions. If you happen to have a chart of common polyatomic ions, you can find out that phosphate is PO4 and has a 3- charge. So, to even out the charges, we need to get three barium ions and two phosphate ions. Now, the total positive charge (from the barium ions) is 6+, and the total negative charge (from the phosphate ions) is 6-.We see that Ba3(PO4)2 is the chemical formula for barium phosphate.
There are 4 step to determine molecular formula, which are given bellow Step:1:- Find empirical formula Step:2:- Find empirical formula mass Step:3:- Find n n=molecular mass/empirical formula mass Step:4:- now find molecular formula to find molecular formula molecular formula(empirical formula)n
Aluminium oxide Al2O3 has a formula mass of: (2X 26.981538) + (3 X 15.9994) = 128.94 = 129 to nearest atomic mass unit.
molar mass over grams of elementThe above answer is somewhat correct. In order to find the molecular formula when given the empirical formula, you must first find the molar mass of the empirical formula.MOLAR MASS# atoms element A x Atomic Mass element A (Periodic Table) = mass A# atoms element B x atomic mass element B (periodic table) = mass B... etc.Add up all of the mass values found above and you have the molar mass.Then, after you have found the empirical formula's molar mass, you divide the molar mass of the molecular formula by the empirical formula's molar mass (solving for n).MOLECULAR FORMULA EQUATION: N (Empirical formula) (read as N times empirical formula) where:N = Molar mass substance---- Molar Mass emp. form.
The formula mass of Ca3(PO4)2 is 3(40.1) + 2[31.0 + 4(16.0)] = 310.3 The atomic masses of the individual elements can be obtained from the perodic table.
The chemical formula for calcium phosphide is Ca3P2.Formula mass of Ca3P2 = 3(40.1)+2(31.0) = 182.3Amount of Ca3P2 = mass of sample / formula mass = 444/182.3 = 2.44mol
Empirical formula = C3H5O Molar mass of empirical formula = 3(12.01)+5(1.008)+1(16) = 57.07 Molar mass of molecular fomula = 114.15 n = Molar mass of molecular fomula/Molar mass of empirical formula = 114.15/57.07 n = 2 Molecular formula = n(empirical formula) Molecular formula = 2(C3H5O) = C6H10O2 Check: 6(12.01)+10(1.008)+2(16)= 114.14
The formula mass of sodium carbonate, Na2CO3 is 2(23.0)+12+3(16) = 106.0Amount of sodium carbonate = mass of sample / formula mass = 4/106.0 = 0.0377mol
The unit CH2 has a gram atomic mass of 12.011 + 2(1.00794) or about 14. 42.0/14 = 3; therefore the molecular formula is C3H3.
the density of an object that is 10 cm by 2 cm and has a mass 400g will be 10000 Kg m-3. This can be calculated by the formula, density = mass/volume
The empirical formula CH2 has a formula mass of 14, and 42.0/14 = 3. Therefore, the molecular formula is C3H6.
Molar (formula) mass of calcium nitrate is 164,1 9/mol Molecular weight calculation: 40.078 + (14.0067 + 15.9994*3)*2
One time the atomic mass of carbon (12 g/mol C) = 12Two times the atomic mass of oxygen (16 g/mol O) = 32Adding up both (totalizing 1*12 and 2*16) gives the molar mass of CO2 = 44 g/mol CO2
399.91 amu Fe(2*55.85)+S(3*32.07)+O(12*16.00)
Cu3(PO4)2 3(GMW of Cu)+2(GMW of P)+8(GMW of O) 3(63.546)+2(30.973)+8(15.999) =380.576
Barium is in Group 2, so we know that it makes 2+ ions. If you happen to have a chart of common polyatomic ions, you can find out that phosphate is PO4 and has a 3- charge. So, to even out the charges, we need to get three barium ions and two phosphate ions. Now, the total positive charge (from the barium ions) is 6+, and the total negative charge (from the phosphate ions) is 6-.We see that Ba3(PO4)2 is the chemical formula for barium phosphate.