the answer we are all looking for is 645!
The Power
Parts of the light Microscope 1. Ocular lens or eyepiece: most are 10x magnification. The scopes used are binocular (two eyepieces). 2. Body tube: contains mirrors and prisms which direct the image to the ocular lenses. 3. Nosepiece: holds the objective lenses, rotates 4. Objective lenses: usually 3-4 on our scopes, 4x, 10x, 43x, 100x oil immersion (red banding). Total magnification = ocular power x objective power. Most of our binocs have fixed position lenses--the stage moves up and down rather then the lens. 5. Stage: Movable platform on which slides are mounted for viewing; all of the scopes have mechanical stages with X,Y vernier scales. Focus knobs move the stage up and down. 6. Condensor: A substage lens which focus the light on the specimen. The binocs have condensors that move up and down to focus the light beam. 7. Iris Diaphragm: the diaphragm is located just below the stage and controls the amount of light which passes to the specimen and can drastically affect the focus of the image. 8. Focusing knobs: outermost is the fine focus and innermost is the coarse focus. On the binocs these knobs control up/down movement of the stage. 9. Light source: The scopes have built in light sources. The rheostat ON/OFF switch is located either on the scope or on the external power supply and is used to regulate light intensity.
what magnification is ontained with the high power objective
The Power
If you mean 3x - 2x * 3x * 43x - 2x * 3x * 43x - 5x * 43x - 20x-17x (negative 17x) is your answer
For x-2x= 3x-43x+1 x-2x= -x and 3x-43x+1 = -40x+1 so -x= -40x+1 subtract -x from both sides 0= -39x +1 -1 = -39x so 1=39x so x=1/39
43x+35 (given the question doesn't define what x is)
9194 It may not be right but this is what i come up with
4300x
It means the zoom power, i.e. how much magnification is possible at the long end of the zoom.
3x - 4 = 83x = 8+43x = 12x = 12/3 = 4
sqrt( 3x + 4 ) = 23x + 4 = 43x = 0x = 0Marvelous.
The enesis is abiological when the abiosis is in the abiotrophy into the abirritate crossing the fuel pump's abju. In other words, (x + 1)^10 = x^10 + 10x^9 + 43x^8 + 118x^7 + 210x^6 + 252x^5 + 210x^4 + 118x^3 + 43x^2
12x-43x=11 -Combine similar terms -31x =11 -Divide both sides by negative 31 -31X/-31=11/-31 -Negative 31 will be cancelled out on the left side X =-0.35 -Solve the right side by dividing 11 by -31 Use the guide from books for the certain answers!!!!!!