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What is the mass (in grams) of 9.52 1024 molecules of methanol (CH3OH)?
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What is the mass (in grams) of 9.18 1024 molecules of methanol (CH3OH)?
9.18x10^24 molecules CH3OH x 1 mole/6.02x10^23 molecules x 32 g/mole = 488 g (to 3 sig figs)
How many molecules are there in 1x1024 molecules of BCl3?
1 x 1024 molecules
How many moles in 4.96 x 1024 molecules of glucose?
4,96 x 1024 molecules of glucose is equal to 8,236 moles.
How do you determine the number of molecules of water you swallow from a cup of water?
A cup is 8 fluid ounces. And 8 ounces is about 236.6 grams of water.There are 18 grams of water in one mole of water, and a mole of anything contains Avogadro's number of molecules of that compound. That's 6.02 x 1023 molecules.Our (236.6 grams of water) divided by (18 grams per mole) = 13.14 moles of waterOur (13.14 moles of water)(6.02 x 1023 molecules per mole) = 7.91 x 1024 molecules in the 8 ounce glass of water.We had 8 ounces of water. We converted to grams. Then we looked up water to see how many grams of water there were in a mole of water. Then we found out how many moles we had in our cup of water. Then, because we knew how many molecules of water were in a mole (we know because a mole of anything is Avogadro's number of particles of that substance), we multiply to find out how many molecules of water were in the cup of water.That's how we found that there are 7.91 x 1024 molecules in a cup of water.
How many moles of molecules are there in 7.6 x 10 to the 24 oxygen molecules?
Given: 7.6 x 1024 O2 moleculesKnown: 1 mole O2 molecules = 6.022 x 1023 molecules O2 moleculesConvert molecules to moles.7.6 x 1024 molecules O2 x (1mol O2/6.022 x 1023 molecules O2) = 13 moles O2 (rounded to two significant figures)
What is the mass in grams of 9.03 X 1024 molecules of methanol CH3OH?
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
What is the mass in grams of 9.32x1024 molecules of methanol CH3OH?
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
What is the mass of 3.62 X 1024 molecules of CH3OH?
192.678 grams CH3OH
What is the mass (in grams) of 9.18 1024 molecules of methanol (CH3OH)?
9.18x10^24 molecules CH3OH x 1 mole/6.02x10^23 molecules x 32 g/mole = 488 g (to 3 sig figs)
What is the mass in grams of 9.47 x 1024 molecules of methonal?
The simplest form of the molecular formula for methanol {note corrected spelling} is CH4O, and its gram molecular mass is 32.04. By definition therefore, a mass of Avogadro's Number of molecules contains 32.04 grams. Avogadro's Number is about 6.022 X 1023. Therefore, 9.47 X 1024 molecules of methanol contains [(9.47 X 1024)/(6.022 X 1023)]32.04 or 504 grams, to the justified number of significant digits.
How many grams are in a sample of sulphur trioxide that has 1.88 x 1024 molecules?
1.88 X 1024 molecules SO3 (1 mole SO3/6.022 X 1023)(80.07 grams/1 mole SO3) = 250 grams sulfur trioxide ===================
How many molecules are there in 200 grams of h2o?
200 grams H2O (1 mole H2O/18.016 grams)(6.022 X 1023/1 mole H2O) = 6.69 X 1024 molecules of water ======================
How many molecules would be found in 427.4 grams of potassium nitrate?
Quite a few! 427.4 grams KNO3 (1 mole KNO3/101.11 grams)(6.022 X 1023/1 mole KNO3) = 2.546 X 1024 molecules of potassium nitrate -----------------------------------------------------------
How many molecules are there in 1x1024 molecules of BCl3?
1 x 1024 molecules
How many molecules are in 2.3 moles of carbon dioxide?
One mole is defined by Avogadro's number of 6. 02x10^23 particles. To solve this equation we multiple Avogadro's number by our given quantity of 2. 10 moles. The answer then is 2. 64x10^24 molecules of CO2.
How many moles in 4.96 x 1024 molecules of glucose?
4,96 x 1024 molecules of glucose is equal to 8,236 moles.
How many kilograms are in 1024 grams?
1.024
