Given: 7.6 x 1024 O2 molecules
Known: 1 mole O2 molecules = 6.022 x 1023 molecules O2 molecules
Convert molecules to moles.
7.6 x 1024 molecules O2 x (1mol O2/6.022 x 1023 molecules O2) = 13 moles O2 (rounded to two significant figures)
The number of molecules in 0.24 moles of oxygen can be calculated using Avogadro's number, which states that there are 6.022 x 10^23 molecules in one mole of any substance. Therefore, there are approximately 1.45 x 10^23 molecules of oxygen in 0.24 moles.
320 grams of oxygen is the equivalent of 10 moles.
The answer is 7,18.10e-10 moles.
The answer is 64,9 moles.
No, this would make 5 moles. This is because water is H2O. This means that for each oxygen molecule used, there will be 2 hydrogen molecules used. In the given equation Only 5 moles of oxygen could be used to pair with all 10 moles of hydrogen, therefore giving you an excess of 5 oxygen molecules.
10 moles of oxygen atoms or 5 moles of oxygen molecules.
The number of molecules in 0.24 moles of oxygen can be calculated using Avogadro's number, which states that there are 6.022 x 10^23 molecules in one mole of any substance. Therefore, there are approximately 1.45 x 10^23 molecules of oxygen in 0.24 moles.
320 grams of oxygen is the equivalent of 10 moles.
The answer is 7,18.10e-10 moles.
The answer is 64,9 moles.
.565 MOLES
3.1445E-07 moles and 1.89299E+17 molecules
1 mole equals 6.022 x 10 to the 23 molecules
No, this would make 5 moles. This is because water is H2O. This means that for each oxygen molecule used, there will be 2 hydrogen molecules used. In the given equation Only 5 moles of oxygen could be used to pair with all 10 moles of hydrogen, therefore giving you an excess of 5 oxygen molecules.
3.21 moles HBr (6.022 X 10^23/1mole HBr) = 1.93 X 10^24 molecules of HBr
20 hydrogen 10 oxygen
12.3 kg=12,300 g 12,300 g/44.01g (molar mass) = 279.5 moles 279.5 moles x (6.02 x 10^23) = 1.68248 x 10^26 x 2 = 3.366 x 10^26 atoms of Oxygen in CO2