1 mol of bromine has 79.904g. 79.904g/mol x 350mol =
The molar mass of tribromine oxide (Br3O) can be calculated by adding up the atomic masses of its constituent atoms. The molar mass of bromine (Br) is approximately 79.90 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol. Therefore, the molar mass of tribromine oxide is approximately 249.70 g/mol.
Yes, that is what is used. Bromine is I think ~51:49 ratio of Br79 and Br81. Therefore it is somewhere in between (79.9g/mol)
the number of atoms is equal to the mass of the sample divided by its molar mass times one mole 11.74g / 58.69g/mol * 6.02*1023 atoms/mol = 1.2*1023 atoms approximately
Chlorine has isotopes with mass numbers ranging from 32 to 40. There are two principal stable isotopes, 35Cl (75.77%) and 37Cl (24.23%), giving chlorine atoms in bulk an apparent atomic weight of 35.5 g/mol.
The molar mass of bromine is approximately 79.9 grams/mol. Since one mole of any substance contains Avogadro's number of particles (6.022 x 10^23), the mass of a single bromine atom is approximately 79.9 grams/mol divided by 6.022 x 10^23, which is approximately 1.33 x 10^-22 grams.
The molar mass of tribromine oxide (Br3O) can be calculated by adding up the atomic masses of its constituent atoms. The molar mass of bromine (Br) is approximately 79.90 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol. Therefore, the molar mass of tribromine oxide is approximately 249.70 g/mol.
The mass depends on the element whose atoms are concerned. For eg, 1 mol Helium atoms have mass 4 g 1 mol Neon atoms have mass 20 g.
Yes, that is what is used. Bromine is I think ~51:49 ratio of Br79 and Br81. Therefore it is somewhere in between (79.9g/mol)
1.54 (mol Br2) * 6.022*10+23 (molecule/mol Br2) * 2 (atoms Br/molecule Br2) =1.85*1024 atoms in 1.54 mole Br2
Mol = mass/Ar (relative atomic mass)For Bromine Ar is 79.9 g/mol.Mol= 0.476/79.9 = 5.96x10-3
the number of atoms is equal to the mass of the sample divided by its molar mass times one mole 11.74g / 58.69g/mol * 6.02*1023 atoms/mol = 1.2*1023 atoms approximately
To determine the molar mass for any compound, you multiply the molar mass of each element (atomic mass in grams) times its subscript, which represents the number of atoms of that element. Then add the result for each element. Molar Mass of P4S3 (4 atoms x 30.974g/mol P) + (3 atoms x 32.06g/mol S) = 123.90g/mol P + 96.18g/mol S = 220.08g/mol P4S3
The mass of 2.000 mol of oxygen atoms is 32.00 grams.
No the number of ATOMS in 1 Bomine MOLECULE Br2 is twice Avagadro's number.
Diamond is made of up carbon. So, it has a molar mass of 12 g/mol. 6 g/mol / 12 g = 0.5 mol 0.5 mol * 6x10^23 atoms/mol = 3x10^23 atoms There are 3x10^23 atoms in six grams of diamond.
(g) -> moles = x(g) * (1 mol/molar mass)Moles -> atoms = x(mol) * (6.022*10^23/1 mol)
Potassium bromide is KBr, so by adding together their molar masses, we get 39+80=119gmol-1