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Atomic mass from my Periodic Table for Zinc is 65.38. This means 1 mole of naturally occurring zinc has a mass of 65.38 grams. If your zinc sample is pure zinc then: (mass of your sample)/(65.38 grams) = # moles of zinc.
0,356 moles of zinc contain 23,27 g.
The answer is 2,7 moles.
To determine the volume of H3PO4 required to react with 4.5 grams of Zinc, we need to convert the mass of Zinc to moles using its molar mass (65.38 g/mol). Then, we use the stoichiometry of the balanced chemical equation to find the corresponding mole ratio between H3PO4 and Zinc (Zn). Finally, we convert the moles of H3PO4 to liters using its molarity (3.0 M).
Zinc has an atomic mass of 65.4
Atomic mass from my Periodic Table for Zinc is 65.38. This means 1 mole of naturally occurring zinc has a mass of 65.38 grams. If your zinc sample is pure zinc then: (mass of your sample)/(65.38 grams) = # moles of zinc.
Is 5.93g ZnCl2
For this you need the atomic mass of Zn. Then take the mass in grams and divide it by the atomic number (multiplied by one mole for units to cancel) to find number of moles. Zinc's atomic mass is 65.4 grams.22.5 g Zn / (65.4 grams) = .344 moles Zn
For this you need the atomic mass of Zn. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.671.89 moles Zn × (65.4 grams)) = 10.3 grams Zn
0,356 moles of zinc contain 23,27 g.
Calculated by dividing mass (in grams) by atomic mass of Zn: 3.45(g) / 65.38(g/mole) = 0.0528 mole
1.88 mol Zn ( 6.022 X10^23/1mol Zn ) = 1.13 X10^24 atoms.
6.228 mole of zinc atom
A theoretical yield is the amount of substance you calculate mathematically, as opposed to the actual yield, which is the amount of substance you find using a balance.To find the theoretical yield, you need a balanced equation. In this case,Zn + I2 -> ZnI2So, that was easy enough. The theoretical yield is limited by the reagent present in the smaller quantity by moles, not by mass. You must take the mass you have of zinc multiplied by zinc's molar mass to find the number of moles of zinc. You must take the mass you have of I2 and multiply by the molar mass of I2.The limiting reagent is the substance of fewer moles. Since these two reagents react in a 1:1 ratio, you just need to compare and see which you have less of. This will give you the number of moles you can make of ZnI2, theoretically -- the theoretical yield.
The answer is 2,7 moles.
2.60 moles
To determine the volume of H3PO4 required to react with 4.5 grams of Zinc, we need to convert the mass of Zinc to moles using its molar mass (65.38 g/mol). Then, we use the stoichiometry of the balanced chemical equation to find the corresponding mole ratio between H3PO4 and Zinc (Zn). Finally, we convert the moles of H3PO4 to liters using its molarity (3.0 M).