15.99 g/mol
Molar mass Na: 23 g/mol O : 16 g/mol H : 1 g/mol Total NaOH: 40 g/mol Mass percentage %Na: 23/40 = 57.5% %O : 16/40 = 40% %H : 1 /40 = 2.5%
22.9 + 35.3 + 15.9 = 74.1 g/mol Na: 22.9 g/mol Cl: 35.3 g/mol O: 15.9 g/mol
The molar mass of fenugreek (C6H4O3) can be calculated by summing the atomic masses of each element: (C: 12.01 g/mol) + (H: 1.01 g/mol) + (O: 16.00 g/mol) x 3. This gives a molar mass of fenugreek of approximately 180.16 g/mol.
2.2 mol water = 2.2 (mol) * 18 (g/mol) water = 39.6 (mol*g/mol) = 40 g18 g/mol = mol mass of H2O = 2*H + 1*O = (2*1 + 16) g/mol
15.99 g/mol
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
I believe it is: %O=mass of 3 mol of O / mass of 1 mol of potassium chlorate *100% If you measured it: %O=mass of oxygen lost / mass of potassium chlorate *100%
The molar mass of Mg O = 40.3044 g/mol
1 mol Na X (22.99 Na / mol Na) = 22.99 g Na1 mol N X (14.01 g N / mol N) = 14.01 g N3 mol O X (16.00 g O / mol O) = 48.00 g OMolar mass of NaNO3 = 85.00 g/mol
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
Atomic mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
Molar Mass of Al: 2(27.0g/mol) = 54.0g/mol Molar Mass of O: 3(16.0g/mol) = 48.0g/mol Molar Mass of compound: 102.0g.mol (54.0g/mol / 102.0g/mol) x 100% = 52.9%
Io (the moon of Jupier) has a mass of 8.9319×1022 kg
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
1 mol Na X (22.99 Na / mol Na) = 22.99 g Na1 mol N X (14.01 g N / mol N) = 14.01 g N3 mol O X (16.00 g O / mol O) = 48.00 g OMolar mass of NaNO3 = 85.00 g/mol
H: 1 g/mol O: 16 g/mol H x 2 = 2 g/mol O x 1 = 16 g/mol 2 g/mol + 16 g/mol = 18 g/mol