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The mass of one mole of oxygen atoms is listed on the periodic table (15.999g). Multiply this by three. Be careful. Oxygen is almost never found outside of a molecule. If you are looking for the mass of three moles of oxygen gas, that is three moles of O2. So, you will need to multiply the mass of the atom by two, then multiply by the number of moles.
The answer is 0,8 moles oxygen.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
Suppose we react 6.00 moles calcium with 4.00 mol oxygen gas. Determine the number of moles of oxygen left over after the reaction is complete.
Oxygen - Atomic Mass: 15.9994.
The mass of 0,2 moles of oxygen gas is 6,4 g.
using the equation moles=mass/molar mass (since its in gas form) O2 => 16*2 =32 0.16/32=0.005 moles :)
28 mass of oxygen
The mass of one mole of oxygen atoms is listed on the periodic table (15.999g). Multiply this by three. Be careful. Oxygen is almost never found outside of a molecule. If you are looking for the mass of three moles of oxygen gas, that is three moles of O2. So, you will need to multiply the mass of the atom by two, then multiply by the number of moles.
If the density of oxygen atSTP is 1,429 g/L the mass of 180 L is 257,22 g.If the mole of oxygen (O2) is 15,999 g the number of moles is 16,077.
The answer is 0,173 moles.
The answer is 0,8 moles oxygen.
6,5 moles oxygen equals 208 g.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
Assuming you mean oxygen gas, the number of molecules can be found by first finding the number of moles = mass of oxygen (4g) / Molecular mass of oxygen gas (32 g mol-1) This tells us there is 0.125 mol of oxygen gas present. The number of molecules present is given by the number of moles x the avogadro constant (6.022x10^23) So the number of oxygen gas molecules present is equal to 0.125 x 6.022x10^23 = 7.5275x10^22 molecules
The equivalent in moles is 6,03.
The answer is 2 moles.