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Q: What is the mass of 4.50 moles of chlorine gas Cl2?
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How many moles are in 15g of chlorine gas?

The molecular mass of chlorine gas, Cl2, is 2(35.5) = 71.0 Amount of Cl2 = 15/71.0 = 0.211mol


How many moles are in 47g of chlorine gas?

4.005


What is 120g of chlorine gas converted into mol?

Remember moles = nass(g) / Mr ( Relative Moleculr Mass) . mass = 120 g Mr =35.5 x 2 = 71 ( Because chlorine exists as a diatomic gas Cl2). Hence moles(Cl2) = 120 /71 = 1.690


How many moles in 79.3g CL2?

The gram molecular mass of Cl2 is 70.906, twice the atomic mass of chlorine atoms. Therefore, 79.3 grams of Cl2 contains 79.3/70.906 or 1.12 moles, to the justified number of significant digits.


Which best represents the number of moles in exactly 84 grams of chlorine (Cl2) gas?

The number of moles in exactly 84 grams of chlorine (Cl2) gas 2,37.


How many moles of iodine are produced from 8.00 moles of chlorine?

You cannot produce any Iodine from chlorine, because chlorine (Cl2, gas) is an element, hence it does not contain any Iodine (I2, solid with purple vapor). However when 8.00 moles Cl2 react with excess (>16) moles potassium Iodide (KI) then also 8.00 moles of Iodine are produced, not FROM but BY MEANS OF chlorine. Cl2 + 2KI --> 2 KCl + I2


How would you find the answer to this question How many moles of HCl can be formed when moles of hydrogen gas react with chlorine?

For each mole of hydrogen gas (H2) reacting with chlorine gas (Cl2), you will get 2 moles of HCl. H2 + Cl2 = 2 HCl


How many moles of PCl5 can be produced from 56.0g Cl2 and excess P4?

To find out how many moles of PCl5 can be formed from the reaction of P4 and Cl2, it is necessary to set up the stoichiometric equation. X P4 + Y Cl2 --> Z PCl5. Balancing the equation, X = 1, Y = 10, and Z = 4. This means that for every mole of P4 that reacts, 4 moles of PCl5 is produced. The next step is to find out how many moles of P4 are present in 30.0 grams. The molar mass of P4 is 123.895 g/mol, so there are .24214 moles of P4 present. Multiplied by 4, the answer is 0.96856 moles of PCl5 are produced.


How many moles of chlorine gas are contained in 9.02 x 1023 atoms?

9.02 X 10^23 atoms Cl2 (1mol Cl2/6.022 X 10^23) = 1.50 moles Cl2


When 4 moles of aluminum are allowed to react with an excess of chlorine gas Cl2 how many moles of aluminum chloride are produced?

4 moles


When 4 moles of aluminum are allowed to react with an excess of chlorine gas CL2 how many moles of aluminum chlorde are produced?

4 moles


What is the maximum mass of aluminum chloride that can be formed when reacting 13.0 of aluminum with 18.0 of chlorine?

I'm assuming you mean 13g of Aluminum and 18g of Chlorine Atomic mass of Al = 27g/mol number of moles = mass / atomic mass = 13g / 27g/mol = 0.481mol Molecular mass of Cl2 = 2(35.5) = 71g/mol number of moles = mass / atomic mass = 18g / 71g/mol = 0.254mol The balanced equation for reaction between Aluminum and Chlorine: 2Al + 3Cl2 --> 2AlCl3 The ratio of Al to Cl2 is 2:3 and there's only 0.254mol of Cl2 therefore it's completely reacted and Al is in excess. The ratio of Cl2 to AlCl3 is 3:2 and 0.254mol of Cl2 so there's (0.254mol x 2/3) = 0.169mol of AlCl3 formed. Molecular mass of AlCl3 : 27 + 3(35.5) = 133.5g/mol mass = number of moles x molecular mass = 0.169mol x 133.5g/mol = 22.56g of AlCl3