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At 22.4 liters a mole at STP, and the molar mass of Cl2 being 71, 17.32 g is about .242 moles. Multiply the moles by standard volume and you get 5.43 liters.
The balanced equation for the reaction between chlorine gas and sodium to form sodium chloride is 2Na + Cl2 → 2NaCl. This means that for every 2 moles of sodium (Na), one mole of chlorine gas (Cl2) reacts to form 2 moles of sodium chloride (NaCl).
Chlorine gas is Cl2. Cl's atomic mass is 35.45 and that x 2 is 70.9
it wouldn't be moles of Cl it would be Cl2 as chlorine doesn't exist as an atom it exsists as two joined to form a compound this is very easy stuff the answer is 15 moles of Cl2 as there 30 moles of Cl hope this helps learn your moles it's easy stuff
Cl2 is chlorine. Chlorine exists as a diatomic molecule.
The molecular mass of chlorine gas, Cl2, is 2(35.5) = 71.0 Amount of Cl2 = 15/71.0 = 0.211mol
4.005
Remember moles = nass(g) / Mr ( Relative Moleculr Mass) . mass = 120 g Mr =35.5 x 2 = 71 ( Because chlorine exists as a diatomic gas Cl2). Hence moles(Cl2) = 120 /71 = 1.690
The gram molecular mass of Cl2 is 70.906, twice the atomic mass of chlorine atoms. Therefore, 79.3 grams of Cl2 contains 79.3/70.906 or 1.12 moles, to the justified number of significant digits.
The number of moles in exactly 84 grams of chlorine (Cl2) gas 2,37.
You cannot produce any Iodine from chlorine, because chlorine (Cl2, gas) is an element, hence it does not contain any Iodine (I2, solid with purple vapor). However when 8.00 moles Cl2 react with excess (>16) moles potassium Iodide (KI) then also 8.00 moles of Iodine are produced, not FROM but BY MEANS OF chlorine. Cl2 + 2KI --> 2 KCl + I2
For each mole of hydrogen gas (H2) reacting with chlorine gas (Cl2), you will get 2 moles of HCl. H2 + Cl2 = 2 HCl
To find out how many moles of PCl5 can be formed from the reaction of P4 and Cl2, it is necessary to set up the stoichiometric equation. X P4 + Y Cl2 --> Z PCl5. Balancing the equation, X = 1, Y = 10, and Z = 4. This means that for every mole of P4 that reacts, 4 moles of PCl5 is produced. The next step is to find out how many moles of P4 are present in 30.0 grams. The molar mass of P4 is 123.895 g/mol, so there are .24214 moles of P4 present. Multiplied by 4, the answer is 0.96856 moles of PCl5 are produced.
9.02 X 10^23 atoms Cl2 (1mol Cl2/6.022 X 10^23) = 1.50 moles Cl2
4 moles
4 moles
I'm assuming you mean 13g of Aluminum and 18g of Chlorine Atomic mass of Al = 27g/mol number of moles = mass / atomic mass = 13g / 27g/mol = 0.481mol Molecular mass of Cl2 = 2(35.5) = 71g/mol number of moles = mass / atomic mass = 18g / 71g/mol = 0.254mol The balanced equation for reaction between Aluminum and Chlorine: 2Al + 3Cl2 --> 2AlCl3 The ratio of Al to Cl2 is 2:3 and there's only 0.254mol of Cl2 therefore it's completely reacted and Al is in excess. The ratio of Cl2 to AlCl3 is 3:2 and 0.254mol of Cl2 so there's (0.254mol x 2/3) = 0.169mol of AlCl3 formed. Molecular mass of AlCl3 : 27 + 3(35.5) = 133.5g/mol mass = number of moles x molecular mass = 0.169mol x 133.5g/mol = 22.56g of AlCl3