Barium (Ba) has an At. No. of 56, and an At. Wt. of 137.36.
(7.8 gm moles) X (137.36 gm/gm mole) = 1071.408 gm.
411.98 grams
The molar mass of barium sulfate, BaSO4 is 233.4 Amount of BaSO4 = mass of sample / molar mass = 14.2/233.4 = 0.0608mol 0.0608 moles of BaSO4 are conained in a 14.2g pure sample.
Molar mass of barium hydroxide, Ba(OH)2 = 171.3Amount of barium hydroxide = mass of sample / molar mass = 317.0/171.3 = 1.85mol
One mole approximately weighs 17g.So 3 moles have a mass of 51g.
4.32 moles Barium (6.022 X 10^23/1 mole Ba) = 2.60 X 10^24 atoms
Molar mass of ammonia = (14.01 + 3.03) (Molar mass of nitrogen + 3 times molar mass of hydrogen, as chemical formula of ammonia is NH3). Molar mass= 17.04 Molar mass x moles = mass 17.04 x 3 = 51.12 Mass of 3 moles of ammonia is 51.12g.
# of moles = grams of substance / molar mass of substance molar mass of Barium =137.33 grams/mole #moles of Barium = 22.3 grams/ 137.33 grams/mole = 0.162382582 moles
The molar mass of barium sulfate, BaSO4 is 233.4 Amount of BaSO4 = mass of sample / molar mass = 14.2/233.4 = 0.0608mol 0.0608 moles of BaSO4 are conained in a 14.2g pure sample.
Molar mass of barium hydroxide, Ba(OH)2 = 171.3Amount of barium hydroxide = mass of sample / molar mass = 317.0/171.3 = 1.85mol
First, we need to find the formula for barium nitrate. Barium's charge is 2+, and nitrate is a 1-. If you criss-cross charges, the resulting formula is Ba(NO3)2. Now that we have the formula, we need to find the atomic mass. Barium has an atomic mass of 137. Nitrate is composed of nitrogen (14.01g) and oxygen (16.00*3 = 48). The atomic mass of nitrate is 62.01. Since there are two NO3 molecules, we multiply by 2 to get 124.02. Finally, we add the barium for a grand total of 261.02. Finally, we set-up our conversion ratios: 432 g Ba(NO3)2/1 * 1 mol/261.02g = 1.66 mols
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.
One mole approximately weighs 17g.So 3 moles have a mass of 51g.
Barium Hydroxide: Mass: 2.74g. Mr = 171. Moles = Mass (g)/Mr Therefore - 2.74/ 171 = 0.01602339181mols.
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
4.32 moles Barium (6.022 X 10^23/1 mole Ba) = 2.60 X 10^24 atoms
Molar mass of ammonia = (14.01 + 3.03) (Molar mass of nitrogen + 3 times molar mass of hydrogen, as chemical formula of ammonia is NH3). Molar mass= 17.04 Molar mass x moles = mass 17.04 x 3 = 51.12 Mass of 3 moles of ammonia is 51.12g.
Need to know the mass of BaCl2 in order to calculate molarity.
The formula of (unhydrated) barium nitrate is Ba(NO3)2. This means, among other things, that each mole contain one mole of barium atoms, two moles of nitrogen atoms, and six moles of oxygen atoms. Thus, the molar mass of this compound is 137.327 + 2(14.007) + 6(15.999) = 261 grams, to three significant digits. 50 moles will then be fifty times this or 1.3 kilograms, to the justified number of significant digits.