The mass number of potassium is about 39. The mass number of bromine is about 80. Total is 119. 119* 2.5 = 297.5. So 297.5 grams of potassium bromide has got 2.5 gram moles.
Potassium bromide is KBr, the atomic mass of this compound is ca. 119.1. no.moles = mass/relitive molecular mass, so in this case that's 245/119.1 = 2.057 moles of KBr.
Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters ) 1.5 M KBr = moles KBr/0.025 Liters = 0.038 moles potassium bromide ------------------
The compound KBr has the name potassium bromide.
0.1868 moles
0.1868 moles
The ionic compound potassium bromide, with formula KBr.
There are two steps to solving this problem:Step 1: Calculate the molar mass of KBr (molar mass is the amount, in grams, that one mole of a substance weighs).From the periodic table, we see that the molar mass of K is 39.10 g/mol (its average atomic mass). Similarly, the molar mass of Br is 79.90 g/mol. Adding these numbers together gives the molar mass of KBr, 119 g/mol.Step 2: Calculate the weight, in grams, using the molar mass and the number of moles.For every one mole of KBr, you have 119 grams of KBr:mass (m) = 119 g/mol * 3.30 molmass (m) = 392.7 gTherefore, 3.30 moles of KBr weighs approximately 392.7 grams.
First write a balanced chemical equation: 2K + Br2 ---> 2KBR Find the limiting reactant by using the moles of each element and determining which one gives you the smallest number of moles of potassium bromide. 2.92 mol K (2 mol KBr/2 mol K)= 2.92 mol KBr 1.78 mol Br2 (2 mol KBR/1 mol Br2)=3.56 mol KBr potassium is your limiting reactant so the max. number of moles of KBr that can be produced is 2.92 mol of KBr
The molar mass of KBr is 119.0023 g/mol
The mass in grams of KBr contained in 2.50 moles of the compound is 2.5 times the sum of the gram atomic masses of hydrogen and bromine, or 2.50(1.008 + 79.904) or 202 grams, to the justified number of significant digits.
357
yes it is because kbr is just one word not 2.