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What is the mass of kbr in 2.50 moles of the compound?

Updated: 4/28/2022
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8y ago

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The mass number of potassium is about 39. The mass number of bromine is about 80. Total is 119. 119* 2.5 = 297.5. So 297.5 grams of potassium bromide has got 2.5 gram moles.

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Lesly Jaskolski

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2y ago
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Q: What is the mass of kbr in 2.50 moles of the compound?
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How many moles are contained in 245g of potassium bromide?

Potassium bromide is KBr, the atomic mass of this compound is ca. 119.1. no.moles = mass/relitive molecular mass, so in this case that's 245/119.1 = 2.057 moles of KBr.


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The compound KBr has the name potassium bromide.


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What compound does bromine potassium stand for?

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How many grams does 3.30 moles of KBr weigh?

There are two steps to solving this problem:Step 1: Calculate the molar mass of KBr (molar mass is the amount, in grams, that one mole of a substance weighs).From the periodic table, we see that the molar mass of K is 39.10 g/mol (its average atomic mass). Similarly, the molar mass of Br is 79.90 g/mol. Adding these numbers together gives the molar mass of KBr, 119 g/mol.Step 2: Calculate the weight, in grams, using the molar mass and the number of moles.For every one mole of KBr, you have 119 grams of KBr:mass (m) = 119 g/mol * 3.30 molmass (m) = 392.7 gTherefore, 3.30 moles of KBr weighs approximately 392.7 grams.


How many moles of potassium bromide can be produced from the reaction of 2.92 moles of potassium with 1.78 moles of bromine gas?

First write a balanced chemical equation: 2K + Br2 ---> 2KBR Find the limiting reactant by using the moles of each element and determining which one gives you the smallest number of moles of potassium bromide. 2.92 mol K (2 mol KBr/2 mol K)= 2.92 mol KBr 1.78 mol Br2 (2 mol KBR/1 mol Br2)=3.56 mol KBr potassium is your limiting reactant so the max. number of moles of KBr that can be produced is 2.92 mol of KBr


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How many atoms of krypton are in 2.50 moles of Kr gas?

The mass in grams of KBr contained in 2.50 moles of the compound is 2.5 times the sum of the gram atomic masses of hydrogen and bromine, or 2.50(1.008 + 79.904) or 202 grams, to the justified number of significant digits.


How many moles of k are needed to form 3.3 moles of KBr?

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